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# If (x # y) represents the remainder that results when the

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CEO
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If (x # y) represents the remainder that results when the [#permalink]  20 Feb 2008, 08:22
If (x # y) represents the remainder that results when the positive integer x is divided by the positive integer y, what is the sum of all the possible values of y such that (16 # y) = 1?
8
9
16
23
24
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You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

CEO
Joined: 21 Jan 2007
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Location: New York City
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Kudos [?]: 169 [0], given: 4

Re: MGMAT - remainder [#permalink]  20 Feb 2008, 08:28
16 = yk + 1, where y is a positive integer and k is an integer
15 = yk

possible values of y are 1+3+5+15 = 24

can soemone tell me why 1 is excluded? the OA is 23
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Director
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Re: MGMAT - remainder [#permalink]  20 Feb 2008, 08:30
bmwhype2 wrote:
16 = yk + 1, where y is a positive integer and k is an integer
15 = yk

possible values of y are 1+3+5+15 = 24

can soemone tell me why 1 is excluded? the OA is 23

because the remainder would be 0.
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Re: MGMAT - remainder [#permalink]  20 Feb 2008, 08:31
bmwhype2 wrote:
16 = yk + 1, where y is a positive integer and k is an integer
15 = yk

possible values of y are 1+3+5+15 = 24

can soemone tell me why 1 is excluded? the OA is 23

1 goes into 16, sixteen times with no remainder.

in other words 16/1 = 16
CEO
Joined: 21 Jan 2007
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Location: New York City
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Re: MGMAT - remainder [#permalink]  20 Feb 2008, 08:33
maratikus wrote:
bmwhype2 wrote:
16 = yk + 1, where y is a positive integer and k is an integer
15 = yk

possible values of y are 1+3+5+15 = 24

can soemone tell me why 1 is excluded? the OA is 23

because the remainder would be 0.

thanks. cant believe i overlooked that.
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You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

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Re: MGMAT - remainder [#permalink]  20 Feb 2008, 18:27
so question basically boils down to: what are the numbers that, when 16 is divided by that number, gives a remainder of 1 ?

quickly, you can get 3, 5 and 15. sum of those 3 numbers are 23
Re: MGMAT - remainder   [#permalink] 20 Feb 2008, 18:27
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