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If |x|-|y|=|x+y|, then which of the following must be true?

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If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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If |x|-|y|=|x+y|, then which of the following must be true?

A. x-y>0
B. x-y<0
C. x+y>0
D. xy>0
E. xy<0

I was unable to find its answer. Hence after trying, I guess the answer is x+y>0.
Please correct me if I am wrong.
Source: Jamboree
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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If x & y are both equal to 0. Then none of the options are true. So if want to find which MUST be true then answer is none. Question should be missing some part i guess.

If the question states that x and y are non zero. Then we can see that x and y should be off opposite polarity to satisfy the equation.
Illustration :

x = 5, y = -1

1)true 2)false 3)true 4) false 5) true

x= -5, y = 1

1)false 2)true 3)false 4) false 5)true

So, answer should be

xy<0

Answer is E
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Thanx for the reply Macfauz. Agree to your illustration but it will be great if you can go with the algebraic method.
Such modulus questions are painful if one doesn't the knows the correct approach.
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Marcab wrote:
if |x|-|y|=|x+y|, then which of the following must be true?
1) x-y>0
2) x-y<0
3) x+y>0
4) xy>0
5) xy<0

I was unable to find its answer. Hence after trying, I guess the answer is x+y>0.
Please correct me if I am wrong.
Source: Jamboree


The correct answer is E, but should be \(xy\leq{0}\) and not \(xy<0\). Otherwise, none of the answers is correct.
The given equality holds for \(x=y=0\), for which none of the given answers is correct.

The given equality can be rewritten as \(|x| = |y| + |x + y|\).
If \(y=0\), the equality becomes \(|x|=|x|\), obviously true.
From the given answers, D cannot hold, and A,B or C holds, depending on the value of \(x\). Corrected E holds.
If \(y>0\), then necessarily \(x\) must be negative, because if \(x>0\), then \(|x+y|>|x|\) (\(x+y>x\)), and the given equality cannot hold.
If \(y<0\), then necessarily \(x\) must be positive, because if \(x<0\), then again \(|x+y|>|x|\) (\(-x-y>-x\)) and the given equality cannot hold.
It follows that \(x\) and \(y\) must have opposite signs or \(y=0\).

Answer corrected version of E \(\,\,xy\leq{0}\).
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Marcab wrote:
Thanx for the reply Macfauz. Agree to your illustration but it will be great if you can go with the algebraic method.
Such modulus questions are painful if one doesn't the knows the correct approach.


Squaring both sides we get :

\((|x| - |y|)^2 = (|x + y|)^2\)

\(|x|^2 + |y|^2 - 2|x||y| = x^2 + y^2 + 2xy\)

So.,

|x||y| = -xy

So -xy is positive (since modulus cannot be negative) and hence xy should be negative.
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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EvaJager wrote:
Marcab wrote:
if |x|-|y|=|x+y|, then which of the following must be true?
1) x-y>0
2) x-y<0
3) x+y>0
4) xy>0
5) xy<0

I was unable to find its answer. Hence after trying, I guess the answer is x+y>0.
Please correct me if I am wrong.
Source: Jamboree


The correct answer is E, but should be \(xy\leq{0}\) and not \(xy<0\). Otherwise, none of the answers is correct.
The given equality holds for \(x=y=0\), for which none of the given answers is correct.

The given equality can be rewritten as \(|x| = |y| + |x + y|\).
If \(y=0\), the equality becomes \(|x|=|x|\), obviously true.
From the given answers, D cannot hold, and A,B or C holds, depending on the value of \(x\). Corrected E holds.
If \(y>0\), then necessarily \(x\) must be negative, because if \(x>0\), then \(|x+y|>|x|\) (\(x+y>x\)), and the given equality cannot hold.
If \(y<0\), then necessarily \(x\) must be positive, because if \(x<0\), then again \(|x+y|>|x|\) (\(-x-y>-x\)) and the given equality cannot hold.
It follows that \(x\) and \(y\) must have opposite signs or \(y=0\).

Answer corrected version of E \(\,\,xy\leq{0}\).


Many thanks for the explanation.
It will be great if you elaborate on how to solve split modulus questions such as given above.
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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New post 22 Oct 2012, 04:26
MacFauz wrote:
Marcab wrote:
Thanx for the reply Macfauz. Agree to your illustration but it will be great if you can go with the algebraic method.
Such modulus questions are painful if one doesn't the knows the correct approach.


Squaring both sides we get :

\((|x| - |y|)^2 = (|x + y|)^2\)

\(|x|^2 + |y|^2 - 2|x||y| = x^2 + y^2 + 2xy\)

So.,

|x||y| = -xy

So -xy is positive (since modulus cannot be negative) and hence xy should be negative.


OR 0, that's why the correct answer should be \(xy\leq{0}\).
Otherwise, very nice solution.
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Re: if |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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New post 22 Oct 2012, 05:01
EvaJager wrote:
MacFauz wrote:
Marcab wrote:
Thanx for the reply Macfauz. Agree to your illustration but it will be great if you can go with the algebraic method.
Such modulus questions are painful if one doesn't the knows the correct approach.


Squaring both sides we get :

\((|x| - |y|)^2 = (|x + y|)^2\)

\(|x|^2 + |y|^2 - 2|x||y| = x^2 + y^2 + 2xy\)

So.,

|x||y| = -xy

So -xy is positive (since modulus cannot be negative) and hence xy should be negative.


OR 0, that's why the correct answer should be \(xy\leq{0}\).
Otherwise, very nice solution.


I was solving on the basis of my previous comment where I had just added the phrase "where x and y are non zero" to the question.

But seeing as how it is much more probable to leave out a <= sign than an entire sentence, I guess the question frame is right and the answer should be xy <= 0
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Re: If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Re: If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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Re: If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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New post 19 May 2016, 09:57
Squaring both sides of equation:-

x^2+y^2 - 2 lxl lyl= x^2 +y^2 +2xy

-lxl lyl= xy

for this to hold true xy should be -ve i.e <0

E is the answer
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Re: If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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New post 08 Jun 2016, 20:54
EvaJager wrote:
Marcab wrote:
if |x|-|y|=|x+y|, then which of the following must be true?
1) x-y>0
2) x-y<0
3) x+y>0
4) xy>0
5) xy<0

I was unable to find its answer. Hence after trying, I guess the answer is x+y>0.
Please correct me if I am wrong.
Source: Jamboree


The correct answer is E, but should be \(xy\leq{0}\) and not \(xy<0\). Otherwise, none of the answers is correct.
The given equality holds for \(x=y=0\), for which none of the given answers is correct.

The given equality can be rewritten as \(|x| = |y| + |x + y|\).
If \(y=0\), the equality becomes \(|x|=|x|\), obviously true.
From the given answers, D cannot hold, and A,B or C holds, depending on the value of \(x\). Corrected E holds.
If \(y>0\), then necessarily \(x\) must be negative, because if \(x>0\), then \(|x+y|>|x|\) (\(x+y>x\)), and the given equality cannot hold.
If \(y<0\), then necessarily \(x\) must be positive, because if \(x<0\), then again \(|x+y|>|x|\) (\(-x-y>-x\)) and the given equality cannot hold.
It follows that \(x\) and \(y\) must have opposite signs or \(y=0\).

Answer corrected version of E \(\,\,xy\leq{0}\).



I think xy=0 wouldn't be the answer because when xy = 0 , either only x or only y can also be zero. Then if x=0 but y is not, then it won't hold true for xy=0. Let me know if I am wrong
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Re: If |x|-|y|=|x+y|, then which of the following must be true? [#permalink]

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New post 08 Jun 2016, 22:46
Marcab wrote:
If |x|-|y|=|x+y|, then which of the following must be true?

A. x-y>0
B. x-y<0
C. x+y>0
D. xy>0
E. xy<0

I was unable to find its answer. Hence after trying, I guess the answer is x+y>0.
Please correct me if I am wrong.
Source: Jamboree


say x = 4 and y = 2. then x+y = 6. |x|-|y| = 2. Not equal. Hence D is out. Also C is out.

Now say x = 4 and y = -2. then x+y = 2. |x|-|y| = 2. Equal. Hence E could be correct. Also B is out.

take Now say x = -4 and y = 2. then |x+y| = 2. |x|-|y| = 2. Equal. Hence A is out.

E is correct option.
Re: If |x|-|y|=|x+y|, then which of the following must be true?   [#permalink] 08 Jun 2016, 22:46
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