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# if x+y <y then is x <y? a) y>0 b)x-y<x

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if x+y <y then is x <y? a) y>0 b)x-y<x [#permalink]

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22 Mar 2004, 17:08
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if x+y <y then is x <y?

a) y>0
b)x-y<x
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shubhangi

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22 Mar 2004, 17:13
Given x+y < y, is x < y

x+y < y ==> x < 0

(1) y is +ve, x is negative..hence x < y
(2) x-y < x
-y < 0, y is +ve, x < y

its D
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22 Mar 2004, 17:20
for the second option..
take for example.. x =3 and y=5 then x-y =-2 which is < 3
but if x =5 and y=4 then also it is < then x... not sufficient..
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shubhangi

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22 Mar 2004, 17:25
shubhangi wrote:
for the second option..
take for example.. x =3 and y=5 then x-y =-2 which is < 3
but if x =5 and y=4 then also it is < then x... not sufficient..

The stem has "x + y < y"

5+4 < 5 (?)
22 Mar 2004, 17:25
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