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If (x + y)/z > 0, is x < 0?

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If (x + y)/z > 0, is x < 0? [#permalink]

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09 Jun 2010, 12:01
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If (x + y)/z > 0, is x < 0?

(1) x < y
(2) z < 0
[Reveal] Spoiler: OA

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Re: OG-DS - Is x < 0 [#permalink]

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09 Jun 2010, 13:09
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mojorising800 wrote:
If (x + y)/z> 0, is x < 0?

(1) x < y
(2) z < 0

If (x + y)/z> 0, is x < 0?

Note that: $$\frac{x+y}{z}>0$$ means that $$x+y$$ and $$z$$ have the same sign - either both positive or both negative.

(1) x < y. No info about z. Not sufficient.
(2) z < 0. No info about y. Not sufficient.

(1)+(2) $$z<0$$ means $$x+y<0$$. Sum $$x+y<0$$ and $$x<y$$ (from 1): $$x+y+x<y$$ --> $$2x<0$$ --> $$x<0$$. Sufficient.

Hope it helps.
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Re: If (x + y)/z > 0, is x < 0? [#permalink]

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26 Dec 2015, 18:36
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Re: If (x + y)/z > 0, is x < 0?   [#permalink] 26 Dec 2015, 18:36
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