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# If (x + y)/z > 0, is x < 0?

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Manager
Status: Its Wow or Never
Joined: 11 Dec 2009
Posts: 208
Location: India
Concentration: Technology, Strategy
GMAT 1: 670 Q47 V35
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WE: Information Technology (Computer Software)
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Kudos [?]: 71 [1] , given: 7

If (x + y)/z > 0, is x < 0? [#permalink]  09 Jun 2010, 11:01
1
KUDOS
00:00

Difficulty:

55% (hard)

Question Stats:

56% (02:01) correct 44% (01:08) wrong based on 18 sessions
If (x + y)/z > 0, is x < 0?

(1) x < y
(2) z < 0
[Reveal] Spoiler: OA

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Math Expert
Joined: 02 Sep 2009
Posts: 27472
Followers: 4312

Kudos [?]: 42232 [2] , given: 5968

Re: OG-DS - Is x < 0 [#permalink]  09 Jun 2010, 12:09
2
KUDOS
Expert's post
mojorising800 wrote:
If (x + y)/z> 0, is x < 0?

(1) x < y
(2) z < 0

If (x + y)/z> 0, is x < 0?

Note that: $$\frac{x+y}{z}>0$$ means that $$x+y$$ and $$z$$ have the same sign - either both positive or both negative.

(1) x < y. No info about z. Not sufficient.
(2) z < 0. No info about y. Not sufficient.

(1)+(2) $$z<0$$ means $$x+y<0$$. Sum $$x+y<0$$ and $$x<y$$ (from 1): $$x+y+x<y$$ --> $$2x<0$$ --> $$x<0$$. Sufficient.

Hope it helps.
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Re: OG-DS - Is x < 0   [#permalink] 09 Jun 2010, 12:09
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# If (x + y)/z > 0, is x < 0?

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