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If (x + y)/z > 0, is x < 0? [#permalink]

09 Jun 2010, 12:01

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If (x + y)/z > 0, is x < 0?

(1) x < y
(2) z < 0

[Reveal] Spoiler: OA

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Re: OG-DS - Is x < 0 [#permalink]

09 Jun 2010, 13:09

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mojorising800 wrote:

If (x + y)/z> 0, is x < 0?

(1) x < y
(2) z < 0

If (x + y)/z> 0, is x < 0?

Note that: \frac{x+y}{z}>0 means that x+y and z have the same sign - either both positive or both negative.

(1) x < y. No info about z. Not sufficient.
(2) z < 0. No info about y. Not sufficient.

(1)+(2) z<0 means x+y<0. Sum x+y<0 and x<y (from 1): x+y+x<y --> 2x<0 --> x<0. Sufficient.

Answer: C.

Hope it helps.
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Re: OG-DS - Is x < 0 [#permalink] 09 Jun 2010, 13:09

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If (x + y)/z > 0, is x < 0?

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