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If x<y<z and y-x>5, where x is an even integer and

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If x5, where x is an even integer and [#permalink] New post 03 Sep 2004, 00:36
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If x<y<z and y-x>5, where x is an even integer and Y and Z are odd integers, what is the least possible value of z-x?

A. 6
B. 7
C. 8
D. 9
E. 10

Please provide the explainations also. Thanks
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 [#permalink] New post 03 Sep 2004, 08:36
B. if y>X+5 and Y and Z are consecutive that means that z>X+6. Considering that all are integers, the answer must be 7.
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 [#permalink] New post 03 Sep 2004, 08:45
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Hold the phone.. Upon further review I think the answer is 9 and here is why. If X is 4 that means that Y has to be 11. If Y is less than Z and both are odd that means that Z has to be 13 and the smallest difference is 9. An odd-even equals an odd. Therefore the smallest difference that is greater than 5 is 7. If Z is a consecutive odd integer that is greater than Y than the answer is 9.
  [#permalink] 03 Sep 2004, 08:45
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If x<y<z and y-x>5, where x is an even integer and

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