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# if x,y,z are integers is x(y^2 + z^3) even?

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Manager
Joined: 22 Sep 2008
Posts: 123
Followers: 1

Kudos [?]: 38 [0], given: 0

if x,y,z are integers is x(y^2 + z^3) even? [#permalink]  29 Sep 2008, 10:40
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(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 2 sessions
Q1:
if x,y,z are integers is x(y^2 + z^3) even?
a: x is odd
b:the product of xyz is odd.

Ithink B is suff. but not sure

Q2:
is x(y+z) >0
a: xyz >0
b: yz>0

I think C will be answer but not sure.
VP
Joined: 18 May 2008
Posts: 1296
Followers: 14

Kudos [?]: 192 [1] , given: 0

Re: DS: x,y,z [#permalink]  29 Sep 2008, 22:28
1
KUDOS
Q2 Is x(y+z) >0
a: xyz >0
b: yz>0

I think it should be E. Combining if yz>0 and xyz>0 then x must be positive. from S2, either y and z have to be positive or both have 2 b -ve.
In case y and z are +ve, then answer is yes.
In case both are -ve then sum of y+z is -ve so the whole ans is also -ve . thus the ans is No. Thus v r getting seperate answ. it shld be E
Director
Joined: 23 May 2008
Posts: 839
Followers: 3

Kudos [?]: 40 [0], given: 0

Re: DS: x,y,z [#permalink]  29 Sep 2008, 22:46
B & E

question 2

together you have +++ for xyz or -++, plug in numbers and find that the equation can be + or -
Re: DS: x,y,z   [#permalink] 29 Sep 2008, 22:46
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