If x,y,z are positive integers and x<y<z, x = ? (1) : DS Archive
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# If x,y,z are positive integers and x<y<z, x = ? (1)

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Senior Manager
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If x,y,z are positive integers and x<y<z, x = ? (1) [#permalink]

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03 Jun 2008, 21:47
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If x,y,z are positive integers and x<y<z, x = ?

(1) the product of x,y,z is odd
(2) The sum of x,y,z is less than 12

I don’t agree with the OA
My pick for this question is B. would appreciate if you guys can contribute to this.
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03 Jun 2008, 22:01
vdhawan1 wrote:
If x,y,z are positive integers and x<y<z, x = ?

(1) the product of x,y,z is odd
(2) The sum of x,y,z is less than 12

I don’t agree with the OA
My pick for this question is B. would appreciate if you guys can contribute to this.

1) says all x y z are odd numbers. insuff
2) insuff on its own. diff combinations 1,2,3 or 2,3,4 etc possible

Together
1,3,5 is the only possible combination

Thus C
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03 Jun 2008, 22:51
vdhawan1 wrote:
If x,y,z are positive integers and x<y<z, x = ?

(1) the product of x,y,z is odd
(2) The sum of x,y,z is less than 12

I don’t agree with the OA
My pick for this question is B. would appreciate if you guys can contribute to this.

yes.
Using 1 , you will see that x,y,z have to be odd
and if the sum is less than 12(using 2)
the only combination is 1,3,5
Senior Manager
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03 Jun 2008, 23:24
Oh k
i got it

For statement 2 (thats how my answer was B) i was making the mistake of picking up numbers for which the product was under 12 ....(but that s like using statement 1 for statement 2)

how dumb of me

thanks for the help guys
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03 Jun 2008, 23:44
alpha_plus_gamma wrote:

Together
1,3,5 is the only possible combination

Thus C

Just a small correction here :
1,3,7 is also a possible combination but with that also x=1 ...so toghether both sufficient if it were asked what is the value of z than answer would be E .
Re: DS question   [#permalink] 03 Jun 2008, 23:44
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# If x,y,z are positive integers and x<y<z, x = ? (1)

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