Fantastic approach. Thanks!
If xy ≠ 0 and x2y2 – xy = 6, which of the following could be y in terms of x?If xy ≠ 0 and x^2*y^2 - xy = 6, which of the following could be y in terms of x?
II. – 2/x
A. I only
B. II only
C. I and II
D. I and III
E. II and III
II. - 2/x
x^2*y^2-xy=6 --> (xy)^2-xy-6=0 --> (xy-3)(xy+2)=0 --> either xy-3=0 and in this case y=3/x or xy+2=0 and in this case y=-2/x.
Answer: E.naaga, please format the questions properly.
P.S. This is your third question for today with incorrect OA.