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If xy ≠ 0, could y be expressed as -2/x? [#permalink]
13 Aug 2009, 07:27
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If xy ≠ 0, could y be expressed as -2/x?
(1) x2y2 – xy = 6
(2) y ≠ 3/x
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Re: If xy ≠ 0, could y be expressed as -2/x? [#permalink]
13 Aug 2009, 08:11
lbsgmat wrote: If xy ≠ 0, could y be expressed as -2/x?
(1) x2y2 – xy = 6
(2) y ≠ 3/x is yx = -2 from 1 xy(xy-1) = 6 , xy can be -2 or 3 ....insuff from 2 obviously insuff both we still dont know whether x,y are intigers or not E
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Re: If xy ≠ 0, could y be expressed as -2/x? [#permalink]
13 Aug 2009, 08:18
lbsgmat wrote: If xy ≠ 0, could y be expressed as -2/x?
(1) x2y2 – xy = 6
(2) y ≠ 3/x SOL: St1: Let xy = m => m^2 - m = 6 => (m+2)*(m-3) = 0 => m = -2 or m = 3 => xy = -2 or xy = 3 => y = -2/x or y = 3/x => NOT SUFFICIENTSt2: => NOT SUFFICIENTSt1 & St2 Together: From I: y = -2/x or y = 3/x From II: y ≠ 3/x => y = -2/x => SUFFICIENTANS: C
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Manager
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Re: If xy ≠ 0, could y be expressed as -2/x? [#permalink]
13 Aug 2009, 08:20
yezz wrote: lbsgmat wrote: If xy ≠ 0, could y be expressed as -2/x?
(1) x2y2 – xy = 6
(2) y ≠ 3/x is yx = -2 from 1 xy(xy-1) = 6 , xy can be -2 or 3 ....insuff from 2 obviously insuff both we still dont know whether x,y are intigers or not E Could you explain why we need to know whether x and y are integers?
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Re: If xy ≠ 0, could y be expressed as -2/x? [#permalink]
13 Aug 2009, 09:24
samrus98 wrote: yezz wrote: lbsgmat wrote: If xy ≠ 0, could y be expressed as -2/x?
(1) x2y2 – xy = 6
(2) y ≠ 3/x is yx = -2 from 1 xy(xy-1) = 6 , xy can be -2 or 3 ....insuff from 2 obviously insuff both we still dont know whether x,y are intigers or not E Could you explain why we need to know whether x and y are integers? Actually i cant  , was just a mistake. C it is
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Re: If xy ≠ 0, could y be expressed as -2/x?
[#permalink]
13 Aug 2009, 09:24
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