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If xy <0, is x>y? 1. x/y <1 2. |x|<|y

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If xy <0, is x>y? 1. x/y <1 2. |x|<|y [#permalink] New post 27 Apr 2004, 05:26
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If xy <0, is x>y?
1. x/y <1
2. |x|<|y|
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 [#permalink] New post 27 Apr 2004, 06:16
E.

If xy <0, is x>y?
If xy< 0; either x< 0 or y<0

1. x/y <1
This is insufficient. x could be negative or y could be negative. If x and y are both negative, that won't help answer the question either.

2. |x|<|y|
If x = -2 and y = 3 then |x| < |y| and x < y BUT
If x = 2 and y = -3 then |x| < |y| and x > y

With statements 1 & 2 together, we're still not able to know if x or y < 0.
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 [#permalink] New post 28 Apr 2004, 15:52
Agree with E
A) is not suff.
x/y = -2/3 <1 --> x<y
x/y = 2/-3 <1 --> x>y
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 [#permalink] New post 08 May 2004, 20:01
I also agree with E since there is no unique value...halle whats the answer?
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Re: DS-64 [#permalink] New post 09 May 2004, 03:09
hallelujah1234 wrote:
If xy <0, is x>y?
1. x/y <1
2. |x|<|y|


1. x < y when y > 0: x < 0, y > 0
x > y when y < 0: x > 0, y < 0

Insufficient

2. x^2 < y^2, nothing about the sign of x+y Insufficient.

1 and 2: Insufficient

E it is
Re: DS-64   [#permalink] 09 May 2004, 03:09
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