If xy = -6, what is the value of xy(x+y)? 1) x-y = 5 2) : DS Archive
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# If xy = -6, what is the value of xy(x+y)? 1) x-y = 5 2)

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If xy = -6, what is the value of xy(x+y)? 1) x-y = 5 2) [#permalink]

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11 Oct 2004, 07:38
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If xy = -6, what is the value of xy(x+y)?
1) x-y = 5
2) x(y^2) = 18
Sorry, I edited option 2 to be more clear.
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Paul

Last edited by Paul on 11 Oct 2004, 09:06, edited 1 time in total.
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11 Oct 2004, 08:31
Paul wrote:
If xy = -6, what is the value of xy(x+y)?
1) x-y = 5
2) xy^2 = 18

Statement 1 gives (5+y)y = -6
that yields y^2 + 5y + 6 = 0
Y=-3, or -2, giving us two values for xy(x+y), thus not sufficient

Statement 2 gives (xy)(y) =18
-6y=18, y = -3 and x = 2, that leds to a specific answer of xy(x + y) = 6,
thus sufficient

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11 Oct 2004, 09:05
Ohh yeah! Cool!

Nice one. I was reading it as (xy)^2 instead of x*y^2. Stupid me!
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12 Oct 2004, 12:11
OA is B. Good job guys.
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Paul

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14 Oct 2004, 13:12
I almost got tricked by the first answer...

14 Oct 2004, 13:12
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