If xy ≠ 0, is xy = 70? (1) x > y (2) x^2 = y^2

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What if x & y = √70
As question doesn't mentioned about x & y whether it is integer or not. So in this case it satisfies B statement.

rajatchopra1994 ... You are right I forgot the root case
If I consider √70 for both, it gives Yes and If I consider other integers, it gives No. Hence, B is also not sufficient.

Combining Statement 1 & 2: We need \(x^2\) = \(y^2\) and X > Y ... so, X has to be +ve and Y has to be -ve.

So, the answer has to be 'E'

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
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Since we have 2 variables (x and y) and 0 equations, C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)

Since \(x^2 = y^2\), we have \(x^2 - y^2 = (x+y)(x-y) = 0\) from the second condition, which means \(x=y\) or \(x=-y\).
However, \(x\) can't be equal to y due to the first condition, \(x = -y.\)
Since \(x\) and \(y\) have different parities, \(xy\) can't be positive number.
Thus, the answer is 'no'

Since both conditions together yield a unique solution, they are sufficient.

Since this question is an inequality question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)

If \(x = 10, y = 7\), then \(xy = 70\) and the answer is 'yes'.
If \(x = 10, y = 6\), then \(xy = 60\) and the answer is 'no'.

Since condition 1) does not yield a unique solution, it is not sufficient


Condition 2)

If \(x = \sqrt{70}\) and \(y = \sqrt{70}\), then we have \(xy = 70\) and the answer is 'yes'.
If \(x = 10\) and \(y = 10\), then we have \(xy = 100\) and the answer is 'no'.

Since condition 2) does not yield a unique solution, it is not sufficient

Therefore, C is the answer.

Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in common mistake types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.

nehasomani33 - This one!!

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