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# If xy+z=z, is |x-y|>0? 1. x# 0 (Not equal to) 2. Y= 0 I

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Re: Confustion modulus problem. [#permalink]  22 May 2011, 20:32
Ohh yes ! That clears up the cloud. Thanks so much...... I was taking the literal meaning of "either". I don't think I ever interpreted "either" as atleast one.

While Karishma's posts are awesome, gurpreetsingh, pike and fluke thanks to you!
Re: Confustion modulus problem.   [#permalink] 22 May 2011, 20:32
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