If xyz>0, is x(y^2)(z^3)>0? 1) y>0 2) x>0 : DS Archive
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# If xyz>0, is x(y^2)(z^3)>0? 1) y>0 2) x>0

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VP
Joined: 29 Dec 2005
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If xyz>0, is x(y^2)(z^3)>0? 1) y>0 2) x>0 [#permalink]

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27 Apr 2006, 19:18
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If xyz>0, is x(y^2)(z^3)>0?

1) y>0
2) x>0
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 8 [0], given: 0

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27 Apr 2006, 19:54
for this case it should be A .

given xyz > 0

take case1 y > 0

say x y z all + so x(y^2)(z^3) > 0

say x - y + and z - so x(y^2)(z^3) > 0

A is suff

take case B x > 0

say x y z all + so x(y^2)(z^3) > 0

say x + y - and z - so x(y^2)(z^3) < 0

B is in suffcient
27 Apr 2006, 19:54
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