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# If xyz>0, is x(y^2)(z^3)>0? 1) y>0 2) x>0

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Joined: 29 Dec 2005
Posts: 1349
Followers: 7

Kudos [?]: 30 [0], given: 0

If xyz>0, is x(y^2)(z^3)>0? 1) y>0 2) x>0 [#permalink]  27 Apr 2006, 19:18
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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If xyz>0, is x(y^2)(z^3)>0?

1) y>0
2) x>0
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 7 [0], given: 0

for this case it should be A .

given xyz > 0

take case1 y > 0

say x y z all + so x(y^2)(z^3) > 0

say x - y + and z - so x(y^2)(z^3) > 0

A is suff

take case B x > 0

say x y z all + so x(y^2)(z^3) > 0

say x + y - and z - so x(y^2)(z^3) < 0

B is in suffcient
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