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If xyz > 0, is (x)(y^2)(z^3) < 0 ? (1) y < 0 (2) x

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Senior Manager
Senior Manager
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Joined: 28 Jun 2007
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Kudos [?]: 10 [0], given: 0

If xyz > 0, is (x)(y^2)(z^3) < 0 ? (1) y < 0 (2) x [#permalink] New post 11 Nov 2007, 08:44
If xyz > 0, is (x)(y^2)(z^3) < 0 ?

(1) y < 0

(2) x > 0
Manager
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Joined: 02 Aug 2007
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Kudos [?]: 11 [0], given: 0

 [#permalink] New post 11 Nov 2007, 09:18
Two cases:
A) Two of these variables are negative
B) All variables are positive


1) Only gives us y, which will be positive regardless
INSUFF
2) Only gives us x, we need to know z to determine the answer
INSUFF

Both:
INCORRECT - See answer below----
SUFFICIENT C.
If we know what y is -ve and x is +ve and xyz > 0, then z must be -ve.

Last edited by yuefei on 11 Nov 2007, 10:20, edited 1 time in total.
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Kudos [?]: 1 [0], given: 0

 [#permalink] New post 11 Nov 2007, 09:24
Here xyz > 0 is given

Now for the above to hold true either all x,y & z must be positive or 2 out of x,y & z must be negative...

Since in statement 1 it is given that y < 0 then it is clear that either of x or z must be negative. In any case (x)(y^2)(z^3) <0> 0.
In this case y and z can both be greater than 0 or less than 0.

So (x)(y^2)(z^3) can be both positive or negative depending on Z..

Hence it should be A
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Kudos [?]: 164 [0], given: 2

 [#permalink] New post 11 Nov 2007, 10:18
yup A makes sense to me as well..
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Kudos [?]: 11 [0], given: 0

 [#permalink] New post 11 Nov 2007, 10:19
I got it. Answer should be A.
Thanks sporty!
  [#permalink] 11 Nov 2007, 10:19
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