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# If xyz 0, is x (y + z) 0? 1) |y + z| = |y| + |z| 2) |x + y|

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SVP
Joined: 05 Jul 2006
Posts: 1519
Followers: 5

Kudos [?]: 115 [0], given: 39

If xyz 0, is x (y + z) 0? 1) |y + z| = |y| + |z| 2) |x + y| [#permalink]  16 Aug 2009, 06:12
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Question Stats:

71% (01:33) correct 29% (01:46) wrong based on 10 sessions
If xyz ≠ 0, is x (y + z) ≥ 0?

1) |y + z| = |y| + |z|
2) |x + y| = |x| + |y|
Director
Joined: 01 Apr 2008
Posts: 906
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 18

Kudos [?]: 304 [0], given: 18

Re: Absolute ds [#permalink]  16 Aug 2009, 07:11
C for me.

stmt 1:
y and z have the same sign
Insuff.

stmt 2:
x and y have the same sign

Combining, x,y and z have the same sign.
If all are positive then x(y+z) > 0.
If all are negative then x(y+z) > 0.
Sufficient.

Last edited by Economist on 16 Aug 2009, 21:35, edited 1 time in total.
Manager
Joined: 05 Jun 2009
Posts: 77
Followers: 1

Kudos [?]: 2 [0], given: 1

Re: Absolute ds [#permalink]  16 Aug 2009, 07:15
Agree with C, either all are negative or all are positive and either means the equation is positive
Senior Manager
Joined: 27 May 2009
Posts: 282
Followers: 2

Kudos [?]: 107 [0], given: 18

Re: Absolute ds [#permalink]  16 Aug 2009, 10:31
x and y have the same magnitude and same sign.

How can you say they both have the same magnitude..pls explain
Manager
Joined: 05 Jun 2009
Posts: 77
Followers: 1

Kudos [?]: 2 [0], given: 1

Re: Absolute ds [#permalink]  16 Aug 2009, 16:30
the magnitude is unimportant, it only asks for if its positive, not how positive is it.
Director
Joined: 01 Apr 2008
Posts: 906
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 18

Kudos [?]: 304 [0], given: 18

Re: Absolute ds [#permalink]  16 Aug 2009, 21:38
rohansherry wrote:
x and y have the same magnitude and same sign.

How can you say they both have the same magnitude..pls explain

Yup, magnitude is not important, I just found a case. However I have corrected my post. x and y can have any magnitude but their signs should be same.
Re: Absolute ds   [#permalink] 16 Aug 2009, 21:38
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# If xyz 0, is x (y + z) 0? 1) |y + z| = |y| + |z| 2) |x + y|

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