Find all School-related info fast with the new School-Specific MBA Forum

It is currently 27 Nov 2014, 23:01

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If xyz 0, is x (y + z) 0? (1) y + z = y + z (2) x + y = x +

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Senior Manager
Senior Manager
avatar
Joined: 08 Nov 2008
Posts: 307
Followers: 2

Kudos [?]: 56 [0], given: 7

If xyz 0, is x (y + z) 0? (1) y + z = y + z (2) x + y = x + [#permalink] New post 29 Mar 2009, 18:57
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

83% (01:00) correct 17% (01:00) wrong based on 9 sessions
If xyz ≠ 0, is x (y + z) ≥ 0?
(1) │y + z│ = │y│ + │z│
(2) │x + y│ = │x│ + │y│
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
_________________

"CEO in making"

Director
Director
avatar
Joined: 14 Aug 2007
Posts: 735
Followers: 7

Kudos [?]: 108 [0], given: 0

Re: DS - Modulas [#permalink] New post 29 Mar 2009, 20:11
tenaman10 wrote:

(1) │y + z│ = │y│ + │z│


=> either y & z are both +ve or both -ve. Insuff as we don't know X.

tenaman10 wrote:

(2) │x + y│ = │x│ + │y│


=> either x&y are both +ve or both -ve. Insuff as we don't know Z.

Together, We have 2 cases
1) x,y,z are all positive:
x (y + z) ≥ 0
2) x,y,z are all -ve.
x (y + z) ≥ 0
Suff.

C
Manager
Manager
avatar
Joined: 19 May 2008
Posts: 165
Location: Mumbai
Followers: 1

Kudos [?]: 3 [0], given: 0

Re: DS - Modulas [#permalink] New post 29 Mar 2009, 20:28
Statement 1, insufficient since we don't know x.
Statement 1, insufficient since we don't know z.

Taking both the statements together, it is xyz not equal to 0. So we can have multiple scenarios.
1 x, y and z are +ve - sufficient
2 x, y and z are -ve - sufficient
2. x is -ve while y and z are positive - not sufficient.

So I think the answer is E. What is the OA?
VP
VP
User avatar
Joined: 05 Jul 2008
Posts: 1434
Followers: 35

Kudos [?]: 235 [0], given: 1

Re: DS - Modulas [#permalink] New post 02 Apr 2009, 19:25
alpha_plus_gamma wrote:
tenaman10 wrote:

(1) │y + z│ = │y│ + │z│


=> either y & z are both +ve or both -ve. Insuff as we don't know X.

tenaman10 wrote:

(2) │x + y│ = │x│ + │y│


=> either x&y are both +ve or both -ve. Insuff as we don't know Z.

Together, We have 2 cases
1) x,y,z are all positive:
x (y + z) ≥ 0
2) x,y,z are all -ve.
x (y + z) ≥ 0
Suff.

C


How can it be C?

x y z are all +ve answer for the Q x(y+z) >= 0 Yes

x y z are all -ve answer for the Q x(y+z) >=0 No

One yes and one No makes it E.
1 KUDOS received
Director
Director
User avatar
Joined: 01 Apr 2008
Posts: 908
Schools: IIM Lucknow (IPMX) - Class of 2014
Followers: 16

Kudos [?]: 251 [1] , given: 18

Re: DS - Modulas [#permalink] New post 02 Apr 2009, 19:45
1
This post received
KUDOS
I go with C. What is OA?

1) y and z have the same sign. So we have two possibilities,
y<0 and z<0 OR
y>0 and z>0

2) x and y have the same sign, So we have two possibilites,
x<0 and y<0 OR
x>0 and y>0

Combining, if we take y<0 and z<0 from (1) then from (2) we will get x<0 ( since from 2, if y<0 then x WILL be < 0).
Hence, x,y,z all have the same sign.
Similarly for the other case.
Hence C.
Senior Manager
Senior Manager
User avatar
Joined: 19 Aug 2006
Posts: 251
Followers: 2

Kudos [?]: 6 [0], given: 0

Re: DS - Modulas [#permalink] New post 04 Apr 2009, 09:26
I go with C.

stmnt 1 - indicates y and z are of the same sign, insuff.
stmnt 2 - indicates x and y are of the same sign, insuff.

combining, it's suffic.
CEO
CEO
User avatar
Joined: 29 Aug 2007
Posts: 2500
Followers: 55

Kudos [?]: 522 [0], given: 19

Re: DS - Modulas [#permalink] New post 16 Apr 2009, 21:40
icandy wrote:
alpha_plus_gamma wrote:
tenaman10 wrote:

(1) │y + z│ = │y│ + │z│


=> either y & z are both +ve or both -ve. Insuff as we don't know X.

tenaman10 wrote:

(2) │x + y│ = │x│ + │y│


=> either x&y are both +ve or both -ve. Insuff as we don't know Z.

Together, We have 2 cases
1) x,y,z are all positive:
x (y + z) ≥ 0
2) x,y,z are all -ve.
x (y + z) ≥ 0
Suff.

C


How can it be C?

x y z are all +ve answer for the Q x(y+z) >= 0 Yes

x y z are all -ve answer for the Q x(y+z) >=0 No

One yes and one No makes it E.




If x, y, and z are all +ve, x(y+z) > 0. Suff.
If x, y, and z are all -ve, x(y+z) > 0. Suff.
_________________

Verbal: new-to-the-verbal-forum-please-read-this-first-77546.html
Math: new-to-the-math-forum-please-read-this-first-77764.html
Gmat: everything-you-need-to-prepare-for-the-gmat-revised-77983.html


GT

1 KUDOS received
Manager
Manager
avatar
Joined: 22 Feb 2009
Posts: 140
Schools: Kellogg (R1 Dinged),Cornell (R2), Emory(Interview Scheduled), IESE (R1 Interviewed), ISB (Interviewed), LBS (R2), Vanderbilt (R3 Interviewed)
Followers: 8

Kudos [?]: 77 [1] , given: 10

Re: DS - Modulas [#permalink] New post 17 Apr 2009, 09:06
1
This post received
KUDOS
tenaman10 wrote:
If xyz ≠ 0, is x (y + z) ≥ 0?
(1) │y + z│ = │y│ + │z│
(2) │x + y│ = │x│ + │y│
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.


x (y + z) ≥ 0?
Deducing the signs of x and (y+z) will be sufficient to answer the question.

(1) │y + z│ = │y│ + │z│

is possible only if both Y and Z are positive or 0. threfore (y+z) is positive or 0. but we dont know the sign of x. so not sufficient.

(2) │x + y│ = │x│ + │y│

For the above reasons, x is also positive.

Combining both we can say that x (y + z) ≥ 0. Therefore C.
Re: DS - Modulas   [#permalink] 17 Apr 2009, 09:06
    Similar topics Author Replies Last post
Similar
Topics:
2 If xyz 0, is x (y + z) 0? (1) y + z = y + z (2) x + y = x + udaymathapati 2 30 Aug 2010, 09:19
If xyz 0, is x (y + z) 0? 1) |y + z| = |y| + |z| 2) |x + y| yezz 5 16 Aug 2009, 06:12
xyz not equal to 0 is x(y+z)=0? 1) |y+z|= |y|+ |z| 2) |x+y|= apollo168 5 02 Sep 2006, 00:42
If xyz ≠ 0, is x (y + z) = 0? (1) y + z = y + z (2) x trickygmat 2 13 Oct 2005, 14:42
xyz <> 0, is x (y + z) = 0? (1) y + z = y + z (2) x + chunjuwu 7 21 Jan 2005, 09:18
Display posts from previous: Sort by

If xyz 0, is x (y + z) 0? (1) y + z = y + z (2) x + y = x +

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.