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# If xyz>0, is xy^2z^3>0 1) y>0 2) x>0

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If xyz>0, is xy^2z^3>0 1) y>0 2) x>0 [#permalink]

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26 Apr 2006, 03:43
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If xyz>0, is xy^2z^3>0

1) y>0
2) x>0
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26 Apr 2006, 03:48
Is it x * (y^2) * (z^3) or ((xy)^2z)^3
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26 Apr 2006, 04:14
Hallo
From A) and the stem XYZ>0,X and Z should be either both pos+ or neg-
and A) is sufficient
From B) X is pos, Y is squared and is always pos but Z can be pos or neg
so B) is insuff
I would go for A)
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26 Apr 2006, 04:23
getzgetzu wrote:
If xyz>0, is xy^2z^3>0

1) y>0
2) x>0

For the inequality, do use brackets and parantheses to make it clearer.
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26 Apr 2006, 04:29
getzgetzu wrote:
If xyz>0, is xy^2z^3>0

1) y>0
2) x>0

from 1) : y> 0 --> xz> 0 because xyz>0
xy^2z^3= (yz)^2 * x* z ..because (yz)^2 > 0 and xz>0 ---> the product>0 ---> suff

2) x> 0 --> yz > 0 ---> y And z > 0 OR y and z < 0
xy^2 > 0 --> the sign of the product depends on z:
+ if z< 0 ---> the product <0
+ if z>0 -----> the product > 0
--->insuff

A it is.
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27 Apr 2006, 19:22
Agree with A
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27 Apr 2006, 20:24
getzgetzu wrote:
If xyz>0, is xy^2z^3>0

1) y>0
2) x>0

very unclear..... imo, this question can be interpreted in three ways. therefore, i have posted it in 3 different ways.
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28 Apr 2006, 02:41
The OA is A. It is an actual test question.
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