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If y >=0, what is value of x 1) /x-3/ >=y 2) /x-3/

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If y >=0, what is value of x 1) /x-3/ >=y 2) /x-3/ [#permalink] New post 28 Oct 2006, 15:50
If y >=0, what is value of x

1) /x-3/ >=y
2) /x-3/ <=-y
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Re: Another inequality [#permalink] New post 28 Oct 2006, 18:13
Sam Kana wrote:
If y >=0, what is value of x

1) /x-3/ >=y
2) /x-3/ <=-y


D?

|x-3| => x-3=y and 3-x=y

since y>=0 then x has to be 3 to satisfy both equations.
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 [#permalink] New post 28 Oct 2006, 19:51
I am waiting to see alternative solution procedures, I will post the answer soon..
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 [#permalink] New post 29 Oct 2006, 19:32
B.

from 1st, you dont get any specific value of x.

from 2. |x-3| must = 0. so x = 3.

hence B>
  [#permalink] 29 Oct 2006, 19:32
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