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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
06 Aug 2012, 01:50
Expert's post
2
This post was BOOKMARKED
SOLUTION
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
\(|y-\frac{1}{2}| < \frac{11}{2}\), is equivalent to \(-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}\).
Add \(\frac{1}{2}\) to each part of the inequality: \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) --> \(-5<y<6\). Only answer C is from this range.
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
An Easy way for this type of Problem is as follows
When ever you see an in equality with modulus remember these two formulas 1.) |x-b| < c .................This always means that ............ -c+b < x < c +b 2.) |x-b| > c ................. This always means that .......... Either x < -c+b .................... or x > c+b
Use this here and see.
Last edited by Narenn on 25 Mar 2014, 20:57, edited 1 time in total.
Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
10 Aug 2012, 03:09
Expert's post
SOLUTION
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
\(|y-\frac{1}{2}| < \frac{11}{2}\), is equivalent to \(-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}\).
Add \(\frac{1}{2}\) to each part of the inequality: \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) --> \(-5<y<6\). Only answer C is from this range.
Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
16 Dec 2012, 06:26
1
This post received KUDOS
Bunuel wrote:
SOLUTION
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
\(|y-\frac{1}{2}| < \frac{11}{2}\), is equivalent to \(-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}\).
Add \(\frac{1}{2}\) to each part of the inequality: \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) --> \(5<y<6\). Only answer C is from this range.
Answer: C.
I might sound stupid but I really could not understand why \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) results in 5<y<6, should not it be -5<y<6
Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
16 Dec 2012, 06:33
1
This post received KUDOS
Expert's post
Drik wrote:
Bunuel wrote:
SOLUTION
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
\(|y-\frac{1}{2}| < \frac{11}{2}\), is equivalent to \(-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}\).
Add \(\frac{1}{2}\) to each part of the inequality: \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) --> \(5<y<6\). Only answer C is from this range.
Answer: C.
I might sound stupid but I really could not understand why \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) results in 5<y<6, should not it be -5<y<6
Yes it should. Typo edited. Thank you. +1. _________________
Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
16 Dec 2012, 07:15
1
This post was BOOKMARKED
Bunuel wrote:
Drik wrote:
Bunuel wrote:
SOLUTION
If \(|y-\frac{1}{2}| < \frac{11}{2}\), which of the following could be a value of y?
(A) -11 (B) -11/2 (C) 11/2 (D) 11 (E) 22
\(|y-\frac{1}{2}| < \frac{11}{2}\), is equivalent to \(-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}\).
Add \(\frac{1}{2}\) to each part of the inequality: \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) --> \(5<y<6\). Only answer C is from this range.
Answer: C.
I might sound stupid but I really could not understand why \(-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}\) results in 5<y<6, should not it be -5<y<6
Yes it should. Typo edited. Thank you. +1.
Thanks Bunnel for such a valuable reply..and +1 for you as well
I was wondering, if the equation stands at -5<y<6, should not it be that both B & C are right.. Thanks
Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]
15 Apr 2015, 23:09
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