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If |y-1/2| < 11/2, which of the following could be a value

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If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 02:49
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The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 02:50
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SOLUTION

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

|y-\frac{1}{2}| < \frac{11}{2}, is equivalent to -\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}.

Add \frac{1}{2} to each part of the inequality: -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} --> -5<y<6. Only answer C is from this range.

Answer: C.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 09:59
well, here are 2 methods -

lets just check answers,beginning with ans C

|11/2- (1/2)| <11/2 yes,of course, since u subtract from the number 11/2 some portion.


method 2-

|y-1/2| < 11/2

if y>1/2, then y-1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6

if y<1/2, then 1/2- y<11/2 , y>6 reject it,since it contradicts with y<1/2

so, now lets check all answer choices and find the answer between 1/2 and 6

btw, do u post 700+ OG13 questions? havent seen them.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 10:33
LalaB wrote:
well, here are 2 methods -

lets just check answers,beginning with ans C

|11/2- (1/2)| <11/2 yes,of course, since u subtract from the number 11/2 some portion.


method 2-

|y-1/2| < 11/2

if y>1/2, then y-1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6

if y<1/2, then 1/2- y<11/2 , y>6 reject it,since it contradicts with y<1/2

so, now lets check all answer choices and find the answer between 1/2 and 6

btw, do u post 700+ OG13 questions? havent seen them.



If y<1/2, then 1/2-y<11/2 ie 1/2-11/2 <y, ie -5<y. so y lies between -5<y<1/2.

Am I correct???
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 10:39
SOURH7WK, yep, u r correct. it is a typo.forgive me all my sins, or only poor computing skills ))
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 06 Aug 2012, 19:54
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Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22







An Easy way for this type of Problem is as follows

When ever you see an in equality with modulus remember these two formulas
1.) |x-b| < c .................This always means that ............ -c+b < x < c +b
2.) |x-b| < c ................. This always means that .......... Either x < -c+b .................... or x > c+b


Use this here and see.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 07 Aug 2012, 10:50
We have to see how far the value of y is on the number line
so basically, what we have here is

The distance of y from 1/2 is< 5.5
so it could be from 5 to 6.

hence answer is C
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 10 Aug 2012, 04:09
SOLUTION

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

|y-\frac{1}{2}| < \frac{11}{2}, is equivalent to -\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}.

Add \frac{1}{2} to each part of the inequality: -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} --> -5<y<6. Only answer C is from this range.

Answer: C.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 14 Dec 2012, 08:53
Why is

|y-1/2| < 11/2 equivalent to -11/2 < |y-1/2| < 11/2

Why am I not seeing this and why didn´t I come up with it?
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 14 Dec 2012, 09:08
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 07:26
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Bunuel wrote:
SOLUTION

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

|y-\frac{1}{2}| < \frac{11}{2}, is equivalent to -\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}.

Add \frac{1}{2} to each part of the inequality: -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} --> 5<y<6. Only answer C is from this range.

Answer: C.



I might sound stupid but I really could not understand why -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} results in 5<y<6, should not it be -5<y<6
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 07:33
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Drik wrote:
Bunuel wrote:
SOLUTION

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

|y-\frac{1}{2}| < \frac{11}{2}, is equivalent to -\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}.

Add \frac{1}{2} to each part of the inequality: -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} --> 5<y<6. Only answer C is from this range.

Answer: C.



I might sound stupid but I really could not understand why -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} results in 5<y<6, should not it be -5<y<6


Yes it should. Typo edited. Thank you. +1.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 08:15
Bunuel wrote:
Drik wrote:
Bunuel wrote:
SOLUTION

If |y-\frac{1}{2}| < \frac{11}{2}, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

|y-\frac{1}{2}| < \frac{11}{2}, is equivalent to -\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}.

Add \frac{1}{2} to each part of the inequality: -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} --> 5<y<6. Only answer C is from this range.

Answer: C.



I might sound stupid but I really could not understand why -\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2} results in 5<y<6, should not it be -5<y<6


Yes it should. Typo edited. Thank you. +1.


Thanks Bunnel for such a valuable reply..and +1 for you as well

I was wondering, if the equation stands at -5<y<6, should not it be that both B & C are right..
Thanks
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 08:49
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 10:36
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The inequality becomes:
-11/2 < y-1/2 < +11/2

Hence, 1/2 has to be added to each inequality:
-11/2 + 1/2 = -5
11/2 + 1/2 = 6

After simplifying, we get:
-5< y < 6
The only option that lies between -5 and 6 is 11/2, which when simplified is 5.5

Thus, the answer has to be C.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 16 Dec 2012, 10:50
Thanks to you all

+1 to Karanamin
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink] New post 18 Dec 2012, 01:56
Ans:

the first case gives us y<6 and the second case gives –(y-1/2)<11/2 so y >-5 only option c falls in the range of -5<y<6 answer (C).
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Re: If |y-1/2| < 11/2, which of the following could be a value   [#permalink] 18 Dec 2012, 01:56
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