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# If |y-1/2| < 11/2, which of the following could be a value

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If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 01:49
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If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 01:50
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SOLUTION

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

$$|y-\frac{1}{2}| < \frac{11}{2}$$, is equivalent to $$-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}$$.

Add $$\frac{1}{2}$$ to each part of the inequality: $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ --> $$-5<y<6$$. Only answer C is from this range.

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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 08:59
well, here are 2 methods -

lets just check answers,beginning with ans C

|11/2- (1/2)| <11/2 yes,of course, since u subtract from the number 11/2 some portion.

method 2-

|y-1/2| < 11/2

if y>1/2, then y-1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6

if y<1/2, then 1/2- y<11/2 , y>6 reject it,since it contradicts with y<1/2

so, now lets check all answer choices and find the answer between 1/2 and 6

btw, do u post 700+ OG13 questions? havent seen them.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 09:33
LalaB wrote:
well, here are 2 methods -

lets just check answers,beginning with ans C

|11/2- (1/2)| <11/2 yes,of course, since u subtract from the number 11/2 some portion.

method 2-

|y-1/2| < 11/2

if y>1/2, then y-1/2 < 11/2 y<6 , so ,we need some number between 1/2 and 6

if y<1/2, then 1/2- y<11/2 , y>6 reject it,since it contradicts with y<1/2

so, now lets check all answer choices and find the answer between 1/2 and 6

btw, do u post 700+ OG13 questions? havent seen them.

If y<1/2, then 1/2-y<11/2 ie 1/2-11/2 <y, ie -5<y. so y lies between -5<y<1/2.

Am I correct???
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 09:39
SOURH7WK, yep, u r correct. it is a typo.forgive me all my sins, or only poor computing skills ))
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  06 Aug 2012, 18:54
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Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

An Easy way for this type of Problem is as follows

When ever you see an in equality with modulus remember these two formulas
1.) |x-b| < c .................This always means that ............ -c+b < x < c +b
2.) |x-b| > c ................. This always means that .......... Either x < -c+b .................... or x > c+b

Use this here and see.

Last edited by Narenn on 25 Mar 2014, 20:57, edited 1 time in total.
Reversed the sign of 2nd inequality
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  07 Aug 2012, 09:50
We have to see how far the value of y is on the number line
so basically, what we have here is

The distance of y from 1/2 is< 5.5
so it could be from 5 to 6.

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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  10 Aug 2012, 03:09
Expert's post
SOLUTION

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

$$|y-\frac{1}{2}| < \frac{11}{2}$$, is equivalent to $$-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}$$.

Add $$\frac{1}{2}$$ to each part of the inequality: $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ --> $$-5<y<6$$. Only answer C is from this range.

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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  14 Dec 2012, 07:53
Why is

|y-1/2| < 11/2 equivalent to -11/2 < |y-1/2| < 11/2

Why am I not seeing this and why didn´t I come up with it?
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  14 Dec 2012, 08:08
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Donnie wrote:
Why is

|y-1/2| < 11/2 equivalent to -11/2 < |y-1/2| < 11/2

Why am I not seeing this and why didn´t I come up with it?

It seems that you need to brush up fundamentals on absolute value.

Theory: math-absolute-value-modulus-86462.html

PS questions on Absolute Values: search.php?search_id=tag&tag_id=58
DS questions on Absolute Values: search.php?search_id=tag&tag_id=37

Tough inequality and absolute value questions: inequality-and-absolute-value-questions-from-my-collection-86939.html

Hope it helps.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 06:26
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Bunuel wrote:
SOLUTION

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

$$|y-\frac{1}{2}| < \frac{11}{2}$$, is equivalent to $$-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}$$.

Add $$\frac{1}{2}$$ to each part of the inequality: $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ --> $$5<y<6$$. Only answer C is from this range.

I might sound stupid but I really could not understand why $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ results in 5<y<6, should not it be -5<y<6
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 06:33
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Expert's post
Drik wrote:
Bunuel wrote:
SOLUTION

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

$$|y-\frac{1}{2}| < \frac{11}{2}$$, is equivalent to $$-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}$$.

Add $$\frac{1}{2}$$ to each part of the inequality: $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ --> $$5<y<6$$. Only answer C is from this range.

I might sound stupid but I really could not understand why $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ results in 5<y<6, should not it be -5<y<6

Yes it should. Typo edited. Thank you. +1.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 07:15
Bunuel wrote:
Drik wrote:
Bunuel wrote:
SOLUTION

If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

$$|y-\frac{1}{2}| < \frac{11}{2}$$, is equivalent to $$-\frac{11}{2}<y-\frac{1}{2}< \frac{11}{2}$$.

Add $$\frac{1}{2}$$ to each part of the inequality: $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ --> $$5<y<6$$. Only answer C is from this range.

I might sound stupid but I really could not understand why $$-\frac{11}{2}+\frac{1}{2}<y< \frac{11}{2}+\frac{1}{2}$$ results in 5<y<6, should not it be -5<y<6

Yes it should. Typo edited. Thank you. +1.

Thanks Bunnel for such a valuable reply..and +1 for you as well

I was wondering, if the equation stands at -5<y<6, should not it be that both B & C are right..
Thanks
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 07:49
Expert's post
Drik wrote:
Thanks Bunnel for such a valuable reply..and +1 for you as well

I was wondering, if the equation stands at -5<y<6, should not it be that both B & C are right..
Thanks

-11/2=-5.5<-5 and we know that -5<y, thus y cannot be -5.5.

Hope it's clear.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 09:36
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The inequality becomes:
-11/2 < y-1/2 < +11/2

Hence, 1/2 has to be added to each inequality:
-11/2 + 1/2 = -5
11/2 + 1/2 = 6

After simplifying, we get:
-5< y < 6
The only option that lies between -5 and 6 is 11/2, which when simplified is 5.5

Thus, the answer has to be C.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2012, 09:50
Thanks to you all

+1 to Karanamin
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  18 Dec 2012, 00:56
Ans:

the first case gives us y<6 and the second case gives –(y-1/2)<11/2 so y >-5 only option c falls in the range of -5<y<6 answer (C).
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  16 Dec 2013, 11:53
Bunuel wrote:
If $$|y-\frac{1}{2}| < \frac{11}{2}$$, which of the following could be a value of y?

(A) -11
(B) -11/2
(C) 11/2
(D) 11
(E) 22

Practice Questions
Question: 14
Page: 154
Difficulty: 600

$$|y-\frac{1}{2}| < \frac{11}{2}$$ <--- basically what this is saying is, "we start at 0.5, and we CANNOT go 5.5 or more steps in either direction"

which means -5 < x < 6

the only one of the options that fit the restriction is 11/2 = 5.5 ... So answer (C)
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  25 Mar 2014, 12:04
If |y-1/2| < 11/2

First calculate origin (y-1/2)=0. Origin is +1/2.

This should be read as distance from origin 1/2 is less than 11/2 units. So there is range here.

So, on the right side of 1/2 we add 11/2 units and on the left side we minus 11/2 units

(1/2-11/2= -5)---------------------(1/2)---------------------(1/2+11/2 = 6)

So our answer must be in range of -5 to 6. -5<y<6

only 11/2 lies in this range. Hence answer.
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Re: If |y-1/2| < 11/2, which of the following could be a value [#permalink]  15 Apr 2015, 23:09
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Re: If |y-1/2| < 11/2, which of the following could be a value   [#permalink] 15 Apr 2015, 23:09

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