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If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]
11 Dec 2012, 03:23

4

This post received KUDOS

00:00

A

B

C

D

E

Difficulty:

65% (hard)

Question Stats:

43% (02:02) correct
57% (01:30) wrong based on 88 sessions

If y = \sqrt{5-x} where x and y are positive integers, what is the remainder when x is divided by 5?

(1) x < 5

(2) y > 1

Another question from me. No OA as this is my own question. Please let me know if you dont agree with my answer and if so, the reason.. . Here goes.. Source : Me..

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]
11 Dec 2012, 03:52

1

This post received KUDOS

Expert's post

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If y = \sqrt{5-x} where x and y are positive integers, what is the remainder when x is divided by 5?

Since square root from a negative number is undefined and y is a positive integer, then 5-x>0 --> x<5. Since also given that x is positive, then 0<x<5, thus x could be 1, 2, 3 or 4. Now, y would be an integer only for x=1 or x=4.

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]
11 Dec 2012, 09:47

1

This post received KUDOS

MacFauz wrote:

If y = \sqrt{5-x} where x and y are positive integers, what is the remainder when x is divided by 5?

(1) x < 5

(2) y > 1

Another question from me. No OA as this is my own question. Please let me know if you dont agree with my answer and if so, the reason.. . Here goes.. Source : Me..

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]
10 Aug 2013, 06:56

y^2 = 5 -x

x= 5 - y^2

(1).

x=1,4 since x<5

(2).

y>1

x=1 hence REM=1

Hence (B) _________________

Rgds, TGC! _____________________________________________________________________ I Assisted You => KUDOS Please _____________________________________________________________________________

Re: If y = (5-x)^1/2 where x and y are integers, what is the [#permalink]
06 Oct 2014, 12:48

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