If y is a negative number greater than -8, is x greater than : GMAT Data Sufficiency (DS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 23 Jan 2017, 02:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If y is a negative number greater than -8, is x greater than

Author Message
TAGS:

### Hide Tags

Intern
Joined: 27 Sep 2009
Posts: 41
Followers: 0

Kudos [?]: 80 [0], given: 4

If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

01 Jun 2010, 19:39
11
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

60% (02:37) correct 40% (01:59) wrong based on 397 sessions

### HideShow timer Statistics

If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y
[Reveal] Spoiler: OA
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [5] , given: 10565

If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

02 Jun 2010, 04:32
5
KUDOS
Expert's post
5
This post was
BOOKMARKED
shekar123 wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y

Given: $$-8<y<0$$.
Q: is x greater than the average of -8 and x? Or: is $$x>\frac{-8+y}{2}$$? --> $$2x>-8+y$$?

-----{-8}-----{average}-----{y} (average of y and -8 is halfway between y and -8).

(1) On the number line, x is closer to -8 than it is to y.

Now, as $$x$$ is closer to $$-8$$ than it ($$x$$) is to $$y$$, then $$x$$ is either in the green area, so less than average OR in the red area, so also less than average. Answer to the question is NO.

Sufficient.

(2) $$x=4y$$ --> is $$2x>-8+y$$? --> is $$8y>-8+y$$? --> is $$y>-\frac{8}{7}$$? We don't now that. Not sufficient. (we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)

Similar question: number-line-problem-22709.html#p719532

Hope it helps.
_________________
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [2] , given: 10565

### Show Tags

02 Jun 2010, 14:52
2
KUDOS
Expert's post
shekar123 wrote:
Bunuel wrote:
shekar123 wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y

Given: $$-8<y<0$$.
Q: is x greater than the average of -8 and x? Or: is $$x>\frac{-8+y}{2}$$? --> $$2x>-8+y$$?

-----{-8}-----{average}-----{y} (average of y and -8 is halfway between y and -8).

(1) On the number line, x is closer to -8 than it is to y.

Now, as $$x$$ is closer to $$-8$$ than it ($$x$$) is to $$y$$, then $$x$$ is either in the green area, so less than average OR in the red area, so also less than average. Answer to the question is NO.

Sufficient.

(2) $$x=4y$$ --> is $$2x>-8+y$$? --> is $$8y>-8+y$$? --> is $$y>-\frac{8}{7}$$? We don't now that. Not sufficient. (we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)

Similar question: number-line-problem-22709.html#p719532

Hope it helps.

I still can't get option (2)...

Stem: $$-8<y<0$$.

Statement:(2) $$x=4y$$

Based on the above 2 informations can we answer whether: $$2x>-8+y$$? No.
If $$y=-1>-8$$, then $$x=-4$$ and $$2x=-8>-8+y=-8-4=-12$$ - answer to the question is YES;
If $$y=-2>-8$$, then $$x=-8$$ and $$2x=-16<-8+y=-8-2=-10$$ - answer to the question is NO.

Two different answers to the question is $$2x>-8+y$$?

Hope it's clear.
_________________
Retired Moderator
Status: The last round
Joined: 18 Jun 2009
Posts: 1310
Concentration: Strategy, General Management
GMAT 1: 680 Q48 V34
Followers: 79

Kudos [?]: 1006 [0], given: 157

### Show Tags

02 Jun 2010, 06:46
Great explanation!! Kudos!!
_________________
Intern
Joined: 27 Sep 2009
Posts: 41
Followers: 0

Kudos [?]: 80 [0], given: 4

### Show Tags

02 Jun 2010, 14:19
Bunuel wrote:
shekar123 wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y

Given: $$-8<y<0$$.
Q: is x greater than the average of -8 and x? Or: is $$x>\frac{-8+y}{2}$$? --> $$2x>-8+y$$?

-----{-8}-----{average}-----{y} (average of y and -8 is halfway between y and -8).

(1) On the number line, x is closer to -8 than it is to y.

Now, as $$x$$ is closer to $$-8$$ than it ($$x$$) is to $$y$$, then $$x$$ is either in the green area, so less than average OR in the red area, so also less than average. Answer to the question is NO.

Sufficient.

(2) $$x=4y$$ --> is $$2x>-8+y$$? --> is $$8y>-8+y$$? --> is $$y>-\frac{8}{7}$$? We don't now that. Not sufficient. (we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)

Similar question: number-line-problem-22709.html#p719532

Hope it helps.

I still can't get option (2)...
Intern
Joined: 27 Sep 2009
Posts: 41
Followers: 0

Kudos [?]: 80 [0], given: 4

### Show Tags

02 Jun 2010, 20:59
great explanation.

Statement:(2) $$x=4y$$

Based on the above 2 informations can we answer whether: $$2x>-8+y$$? No.
If $$y=-1>-8$$, then $$x=-4$$ and $$2x=-8>-8+y=-8-4=-12$$ - answer to the question is YES;
If $$y=-2>-8$$, then $$x=-8$$ and $$2x=-16<-8+y=-8-2=-10$$ - answer to the question is NO.

Two different answers to the question is $$2x>-8+y$$?
great explanation
Hope it's clear.[/quote]
Director
Status: Apply - Last Chance
Affiliations: IIT, Purdue, PhD, TauBetaPi
Joined: 17 Jul 2010
Posts: 690
Schools: Wharton, Sloan, Chicago, Haas
WE 1: 8 years in Oil&Gas
Followers: 15

Kudos [?]: 147 [0], given: 15

### Show Tags

19 Sep 2010, 15:19
A is enough... Basically it is asking if x is closer to y or -8?, A gives us the answer...

Posted from my mobile device
_________________

Consider kudos, they are good for health

Retired Moderator
Joined: 02 Sep 2010
Posts: 805
Location: London
Followers: 105

Kudos [?]: 958 [0], given: 25

### Show Tags

19 Sep 2010, 15:23
zisis wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.

(2) x = 4y

A is enough, if x is closer to -8 than y and y>-8 then x will be less than the average of -8 and y (answering NO to the question)

B is not enough. Eg. y=-0.5, x=-2, avg=-4.25 x is greater; y=-6, x=-24, avg=-16 x is lesser

Hence, ans is A
_________________
Manager
Joined: 23 Sep 2009
Posts: 151
Followers: 1

Kudos [?]: 96 [0], given: 37

### Show Tags

19 Sep 2010, 15:24
zisis wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.

(2) x = 4y

I just substituted numbers in each of the choices and arrived at A. But it took me 3:05 mins to solve this...I am always taking extra time in solving such problems...ANyone please suggest a short cut in solving such type of problems...Always when I substitute values in these kind of problems I take a minimum of 3 minutes..
Any suggestion is greatly appreciated.

Choice (A)
_________________

Thanks,
VP

Retired Moderator
Joined: 02 Sep 2010
Posts: 805
Location: London
Followers: 105

Kudos [?]: 958 [0], given: 25

### Show Tags

19 Sep 2010, 15:28
vigneshpandi wrote:
I just substituted numbers in each of the choices and arrived at A. But it took me 3:05 mins to solve this...I am always taking extra time in solving such problems...ANyone please suggest a short cut in solving such type of problems...Always when I substitute values in these kind of problems I take a minimum of 3 minutes..
Any suggestion is greatly appreciated.

Choice (A)

In this question, if you draw a number line, most of the answer will just come to you as obvious
_________________
Manager
Joined: 23 Sep 2009
Posts: 151
Followers: 1

Kudos [?]: 96 [0], given: 37

### Show Tags

19 Sep 2010, 15:53
Thank you guys..I will use it going forward...
_________________

Thanks,
VP

Manager
Joined: 07 Aug 2010
Posts: 83
Followers: 1

Kudos [?]: 18 [0], given: 9

### Show Tags

14 Oct 2010, 18:49
A

1) x is closer to -8 than y so x is towards -8 away from mid-point (=avg). so x is < avg ==> SUFF

2) x = 4y

y=-7 => x=-28 --> no
y=1 => x=4 ---> yes
no and yes ==> INSUFF
_________________

Click that thing - Give kudos if u like this

Intern
Joined: 12 Dec 2010
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

17 Jan 2011, 09:40
'A' can't be the correct answer -

given --> -8<y<0

so , when y =-1 , [-1+(-8)] /2=-4.5
when y=-7, [-7+(-8)]/2= -7.5

now if x is closer to -8 means , x<-4.5

but there is no connection between values of X and Y [ie, value of x is independent of Y] so,
if x=-4.6 then , x>-7.5 [where -7.5 is one of the values of average of y and -8]
if x=-7.8 then , x<-7.5 [where -7.5 is one of the values of average of y and -8]

but if x=4y is also considered then x will always be greater than average of y and -8

so correct ans must be C .

please correct me if i'm wrong
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [0], given: 10565

### Show Tags

17 Jan 2011, 09:52
reg wrote:
'A' can't be the correct answer -

given --> -8<y<0

so , when y =-1 , [-1+(-8)] /2=-4.5
when y=-7, [-7+(-8)]/2= -7.5

now if x is closer to -8 means , x<-4.5

but there is no connection between values of X and Y [ie, value of x is independent of Y] so,
if x=-4.6 then , x>-7.5 [where -7.5 is one of the values of average of y and -8]
if x=-7.8 then , x<-7.5 [where -7.5 is one of the values of average of y and -8]

but if x=4y is also considered then x will always be greater than average of y and -8

so correct ans must be C .

please correct me if i'm wrong

OA (official answer) for this question is A. not C.

If you consider y=-7 so that the average of -8 and y to be -7.5 then x=-4.6 is not a proper value for x as (1) says that x is closer to -8 than it (x) is to y.

Refer to the correct solutions above.
_________________
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [0], given: 10565

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

31 Aug 2013, 05:22
Bumping for review and further discussion.
_________________
Senior Manager
Joined: 15 Aug 2013
Posts: 328
Followers: 0

Kudos [?]: 53 [0], given: 23

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

01 Nov 2014, 14:59
Bunuel wrote:
shekar123 wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y

Given: $$-8<y<0$$.
Q: is x greater than the average of -8 and x? Or: is $$x>\frac{-8+y}{2}$$? --> $$2x>-8+y$$?

-----{-8}-----{average}-----{y} (average of y and -8 is halfway between y and -8).

(1) On the number line, x is closer to -8 than it is to y.

Now, as $$x$$ is closer to $$-8$$ than it ($$x$$) is to $$y$$, then $$x$$ is either in the green area, so less than average OR in the red area, so also less than average. Answer to the question is NO.

Sufficient.

(2) $$x=4y$$ --> is $$2x>-8+y$$? --> is $$8y>-8+y$$? --> is $$y>-\frac{8}{7}$$? We don't now that. Not sufficient. (we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)

Similar question: number-line-problem-22709.html#p719532

Hope it helps.

Hi Bunuel,

What exactly do you mean by "(we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)"

I can follow everything minus that. Thanks!
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [0], given: 10565

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

02 Nov 2014, 05:28
russ9 wrote:
Bunuel wrote:
shekar123 wrote:
If y is a negative number greater than -8, is x greater than the average (arithmetic mean) of y and -8 ?

(1) On the number line, x is closer to -8 than it is to y.
(2) x = 4y

Given: $$-8<y<0$$.
Q: is x greater than the average of -8 and x? Or: is $$x>\frac{-8+y}{2}$$? --> $$2x>-8+y$$?

-----{-8}-----{average}-----{y} (average of y and -8 is halfway between y and -8).

(1) On the number line, x is closer to -8 than it is to y.

Now, as $$x$$ is closer to $$-8$$ than it ($$x$$) is to $$y$$, then $$x$$ is either in the green area, so less than average OR in the red area, so also less than average. Answer to the question is NO.

Sufficient.

(2) $$x=4y$$ --> is $$2x>-8+y$$? --> is $$8y>-8+y$$? --> is $$y>-\frac{8}{7}$$? We don't now that. Not sufficient. (we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)

Similar question: number-line-problem-22709.html#p719532

Hope it helps.

Hi Bunuel,

What exactly do you mean by "(we've gotten that if $$0>y>-\frac{8}{7}$$ (for instance if $$y=-1$$), then the answer to the question is YES, but if $$y\leq{-\frac{8}{7}}$$ (for instance if $$y=-2$$), then the answer to the question is NO.)"

I can follow everything minus that. Thanks!

'
For (2) we know that $$x=4y$$. After substituting this into the question the question becomes "is $$y>-\frac{8}{7}$$?" We cannot asnwer this, so the statement is insufficient.

Hope it's clear.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13508
Followers: 577

Kudos [?]: 163 [0], given: 0

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

24 Dec 2015, 06:20
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Director
Joined: 05 Mar 2015
Posts: 607
Followers: 6

Kudos [?]: 81 [0], given: 36

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

11 Oct 2016, 04:45
Bunuel wrote:
reg wrote:
'A' can't be the correct answer -

given --> -8<y<0

so , when y =-1 , [-1+(-8)] /2=-4.5
when y=-7, [-7+(-8)]/2= -7.5

now if x is closer to -8 means , x<-4.5

but there is no connection between values of X and Y [ie, value of x is independent of Y] so,
if x=-4.6 then , x>-7.5 [where -7.5 is one of the values of average of y and -8]
if x=-7.8 then , x<-7.5 [where -7.5 is one of the values of average of y and -8]

but if x=4y is also considered then x will always be greater than average of y and -8

so correct ans must be C .

please correct me if i'm wrong

OA (official answer) for this question is A. not C.

.

how could Ans be A??

if x=-7 and y=-6.5 then Avg. = -8-6.5/2=-7.25 and x> avg.
But if x=-7 and y=-1 then avg. = -8-1/2=-4.5 thus x<avg.

Thanks
Math Expert
Joined: 02 Sep 2009
Posts: 36604
Followers: 7099

Kudos [?]: 93496 [0], given: 10565

Re: If y is a negative number greater than -8, is x greater than [#permalink]

### Show Tags

11 Oct 2016, 05:04
rohit8865 wrote:
Bunuel wrote:
reg wrote:
'A' can't be the correct answer -

given --> -8<y<0

so , when y =-1 , [-1+(-8)] /2=-4.5
when y=-7, [-7+(-8)]/2= -7.5

now if x is closer to -8 means , x<-4.5

but there is no connection between values of X and Y [ie, value of x is independent of Y] so,
if x=-4.6 then , x>-7.5 [where -7.5 is one of the values of average of y and -8]
if x=-7.8 then , x<-7.5 [where -7.5 is one of the values of average of y and -8]

but if x=4y is also considered then x will always be greater than average of y and -8

so correct ans must be C .

please correct me if i'm wrong

OA (official answer) for this question is A. not C.

.

how could Ans be A??

if x=-7 and y=-6.5 then Avg. = -8-6.5/2=-7.25 and x> avg.
But if x=-7 and y=-1 then avg. = -8-1/2=-4.5 thus x<avg.

Thanks

How is x=-7 closer to -8 than x=-7 is to y=-6.5?
_________________
Re: If y is a negative number greater than -8, is x greater than   [#permalink] 11 Oct 2016, 05:04
Similar topics Replies Last post
Similar
Topics:
4 If x and y are both positive numbers, is x greater than 75% of y? 3 22 Aug 2016, 01:50
2 Is x greater than y? 3 17 Jan 2016, 10:11
2 Is x greater than y? 3 23 Jul 2013, 02:55
2 If x is a negative integer greater than -10 3 24 Nov 2012, 08:36
3 Is x greater than y? 5 29 Oct 2011, 09:00
Display posts from previous: Sort by