If y is an integer and y = |x| + x, is y = 0?
(1) x < 0 sufficient
(2) y < 1sufficient
If x is negative and we are adding the absolute value of x with the value of x, then this sum will always = 0.
x = -1
y = |-1| + -1
y = 1 - 1 = 0
x = -2
y = |-2| + -2
y = 2 - 2 = 0
The answer is yes and always yes.
(2) Sufficient because we can answer the question "Yes, y is = to 0, and it is always = 0 when y < 1. We're told in the stem that y is an integer, so we cannot think about fractions. Integers less than y are 0 and negative integers. So can y = a negative integer at all? No. if y = |x| + x, we're either going to have a postive value for x, such as 3. y = |3| + 3; y = 6. or 0, because if x = 0; y = |0| + 0...'nuff said. Or if x is a negative number. x = -3; y = |-3| + -3; y = 3 -3 = 0. Y can NEVER be negative, so this is sufficient to answer the question definitively one way or the other.
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.
Nice explanation. Thanks I had picked A Before I saw this one. you guys are really gr8 helping me out in correcting my silly errors