if y is an integer and y=|x| +x, is y = 0?
2. y <1
Both are sufficient independently.
1. x < 0 , then |x| + x is zero as they cancel out
2. y < 1: Y being an integer limits the possible values to 0 or -ve numbers. It is impossible to generate a negative number using the equation |x| +x which means the only possible value for y is 0.