devinawilliam83 wrote:

If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

(2) y < 1

I rephrased the original question as Is x<0?

Statement 1 : SF

Statement II : if y<1; x+|x|<1..on solving we get 2 ranges for x

- X<0 or,

- 0<X<0.5

Basis this II is insufficient.. Where am I going wrong ?

point to remember is

y is an integer if y<1 , then y could be 0, -1, -2 and so on .. here according to the second condition if x= 0 then y= 0 , if x = -ve then Y = 0 , if x = +ive like 1 then second choice only will fail, if x = 0.5 then y cant be less than one, if x=.2 or .3 then y cant be integer.