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If y is an integer and y = |x| + x, is y = 0?

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If y is an integer and y = |x| + x, is y = 0? [#permalink] New post 21 Feb 2012, 21:07
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If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1


I rephrased the original question as Is x<0?
Statement 1 : SF
Statement II : if y<1; x+|x|<1..on solving we get 2 ranges for x
- X<0 or,
- 0<X<0.5
Basis this II is insufficient.. Where am I going wrong ?
[Reveal] Spoiler: OA
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Re: If y is an integer and y = |x| + x, is y = 0? (1) x < 0 [#permalink] New post 21 Feb 2012, 21:19
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2. If y is an integer and y = |x| + x, is y = 0?
(1) x < 0
(2) y < 1

Notice that since \(y=|x|+x\) then \(y\) is never negative. If \(x>{0}\) (so if x is positive) then \(y=x+x=2x\) and for \(x\leq{0}\) then (when x is negative or zero) then \(y=-x+x=0\).

(1) \(x<0\) --> \(y=|x|+x=-x+x=0\). Sufficient.

(2) \(y<1\), as we concluded y is never negative, and we are given that \(y\) is an integer, hence \(y=0\). Sufficient.

Answer: D.

For hard inequality and absolute value questions with detailed solutions check this: inequality-and-absolute-value-questions-from-my-collection-86939-40.html

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Re: If y is an integer and y = |x| + x, is y = 0? (1) x < 0 [#permalink] New post 21 Feb 2012, 21:43
Bunuel,why didn't i get it with the way i solved it?
Am unable to understand where my approach is wrong . Thanks
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Re: If y is an integer and y = |x| + x, is y = 0? (1) x < 0 [#permalink] New post 21 Feb 2012, 22:35
Expert's post
devinawilliam83 wrote:
Bunuel,why didn't i get it with the way i solved it?
Am unable to understand where my approach is wrong . Thanks


You forgot that it's given that y=integer. (2) says y<1, thus |x|+x must also be some integer less than 1: 0, -1, ... but if you refer to my solution you'll see that |x|+x can never be negative, so the only valid solution for |x|+x (or which is the same for y) is 0.

Hope it's clear.
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Re: If y is an integer and y = |x| + x, is y = 0? [#permalink] New post 04 Jul 2013, 00:24
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Bumping for review and further discussion*. Get a kudos point for an alternative solution!

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Theory on Abolute Values: math-absolute-value-modulus-86462.html

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Hard set on Abolute Values: inequality-and-absolute-value-questions-from-my-collection-86939.html

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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: If y is an integer and y = |x| + x, is y = 0? [#permalink] New post 07 Jul 2013, 18:30
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0

y = |x| + x
y=-x+x
y=0
SUFFICIENT

(2) y < 1
TRICKYYYYYY
I originally said it was insufficient because it tells us nothing about the sign. However, if y is less than one and is an integer and it is equal to |x|+x then it must be zero!!
SUFFICIENT

(D)
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Re: If y is an integer and y = |x| + x, is y = 0? [#permalink] New post 07 Sep 2014, 01:25
devinawilliam83 wrote:
If y is an integer and y = |x| + x, is y = 0?

(1) x < 0
(2) y < 1


I rephrased the original question as Is x<0?
Statement 1 : SF
Statement II : if y<1; x+|x|<1..on solving we get 2 ranges for x
- X<0 or,
- 0<X<0.5
Basis this II is insufficient.. Where am I going wrong ?


point to remember is y is an integer

if y<1 , then y could be 0, -1, -2 and so on .. here according to the second condition if x= 0 then y= 0 , if x = -ve then Y = 0 , if x = +ive like 1 then second choice only will fail, if x = 0.5 then y cant be less than one, if x=.2 or .3 then y cant be integer.
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Re: If y is an integer and y = |x| + x, is y = 0? [#permalink] New post 19 Jan 2015, 00:14
stat 1: X<0 => y = -x+x =0
suff
stat 2:y is in integer & y<1 => y<=0 ...y can be less than zero only when x is less than zero => y = -x+x = 0 and for y=0...ntn to calculate
suff
=> Ans D
Re: If y is an integer and y = |x| + x, is y = 0?   [#permalink] 19 Jan 2015, 00:14
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