If y is an integer is y^3 divisible by 9

(1) y is divisible by 4

(2) y is divisible by 6

OG answer is B - reason if y is divisible by 3 then y is divisble by 9

y is divisible by 6 so y is divisible by 3 and y is dvisible by 9

How is this possible - statement 2 means that Y is divisible by 6. Now Y is an integer therefore to be evenly divisible by 6 - y must be a multiple of 6.

Not all multiples of 6 are divisible by 9.

eg if Y = 12 then y is divisible by 6 but not divisible by 9

if Y = 18 then y is divisible by 6 and also by 9

So My answer is E

Could please someone help explain the OG answer