If y is an integer, is y(cube) divisible by 8?
(1) y is even.
(2) y(cube)- y is even.
Shouldn't the answer be E because y could be 0 which is an even integer?
0 is even and it is divisible by 8. 0 is divisible by any non-zero integer.
for some integer k,
obviously divisible by 8.
(2) Check for example for y=1
and y = 2.
You obtain 0 and 6. Both are even, but 6 is not divisible by 8.
is the product of three consecutive integers, therefore it is always even.
PhD in Applied Mathematics
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