Find all School-related info fast with the new School-Specific MBA Forum

It is currently 22 Oct 2014, 16:59

Starting Soon!

Live Q&A Session with HKU Admissions Team | Join the chat room to participate.


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If y is an integer, y=|x|+x, is y=0? 1)x<0 2)y<1

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Senior Manager
Senior Manager
avatar
Joined: 24 Oct 2006
Posts: 341
Followers: 1

Kudos [?]: 16 [0], given: 0

If y is an integer, y=|x|+x, is y=0? 1)x<0 2)y<1 [#permalink] New post 27 Dec 2006, 23:16
If y is an integer, y=|x|+x, is y=0?

1)x<0
2)y<1
Director
Director
User avatar
Joined: 05 Feb 2006
Posts: 904
Followers: 1

Kudos [?]: 34 [0], given: 0

 [#permalink] New post 28 Dec 2006, 00:51
I must pick A....

If x is less than 0 then you take any value and you will get y=0

x=-0.5
0.5-0.5=0

x=-1.8
1.8-1.8=0.....
So on.....

B is obviously not enougth....
Senior Manager
Senior Manager
avatar
Joined: 23 Jun 2006
Posts: 388
Followers: 1

Kudos [?]: 305 [0], given: 0

 [#permalink] New post 28 Dec 2006, 02:06
in fact, st2 is sufficient as well so answer is D.

st1 is sufficient as noted above:
if x<0 then |x|=-x
so y=|x|+x = -x+x = 0
suff.

st2 is sufficient as well:
from stem only we can deduce that y is non-negative:
if x<0 then y=0 as we showed above,
if x=0 then obviously y=0.
if x>0 then |x|=x and y = 2x > 0

also note that y is an integer (!!!!!!!)

st2 says y<1. the only non-negative integer less than 1 is 0.
so y must be 0.

hence sufficient.


answer is D.
Director
Director
User avatar
Joined: 30 Nov 2006
Posts: 592
Location: Kuwait
Followers: 11

Kudos [?]: 154 [0], given: 0

 [#permalink] New post 28 Dec 2006, 03:18
I'd go with D

Given: y is integer, y = |x| + x
asked : does y = 0 ?


from the question, 0=< y =< infinity; that is, y can range between zero and any positive integer.

because |x| is always positive.
if x is positive then y = 2x
if x is negative then y = 0


(1) x<0
--------------
x is negative then y = x - x = 0 .. YES y = 0

statement 1 is sufficient

(2) y<1
--------------
the only possible value for y < 1 is zero because y can never be negative and y is an integer so it can't be some fraction less than 1 like 1/2 or so.

So y in this case has to equal zero [ y = 0 ]

statement 2 is sufficient


Answer is : D
Director
Director
User avatar
Joined: 05 Feb 2006
Posts: 904
Followers: 1

Kudos [?]: 34 [0], given: 0

 [#permalink] New post 28 Dec 2006, 03:58
Damn, again, i somehow tend to misread this "interger" thing.... yes should be D...
Senior Manager
Senior Manager
avatar
Joined: 24 Oct 2006
Posts: 341
Followers: 1

Kudos [?]: 16 [0], given: 0

 [#permalink] New post 28 Dec 2006, 06:57
You are right! OA is D

Mind works better after a good night's sleep!
VP
VP
User avatar
Joined: 25 Jun 2006
Posts: 1176
Followers: 2

Kudos [?]: 44 [0], given: 0

 [#permalink] New post 28 Dec 2006, 21:22
D.

y can be only >= 0. so (2) is actually Suff.
Senior Manager
Senior Manager
avatar
Joined: 08 Jun 2006
Posts: 343
Location: Washington DC
Followers: 1

Kudos [?]: 14 [0], given: 0

 [#permalink] New post 30 Dec 2006, 18:22
D for me too

From 1) Obvious

From 2)
Possible values of Y is 0 or negative..but negative is not possible because y = |x| + x

|x| + x could be either positive or 0.
Senior Manager
Senior Manager
User avatar
Joined: 24 Nov 2006
Posts: 351
Followers: 1

Kudos [?]: 11 [0], given: 0

 [#permalink] New post 30 Dec 2006, 23:52
y=|x|+x = {0 for x<0; 0 for x=0; 2x for x>0}

Both (1) and (2) are suff to arrive at a single solution, then D.
  [#permalink] 30 Dec 2006, 23:52
    Similar topics Author Replies Last post
Similar
Topics:
2 Experts publish their posts in the topic If y is an integer and y=|x|+x, is y=0? Fijisurf 10 14 Dec 2010, 21:03
1 If Y is an integer and Y = |X| + X, is Y = 0 X<0 Y<1 Allana25 7 11 Mar 2009, 05:58
y is not zero, is (2^x/y)^x<1? 1). x>y 2). y< 0 rampuria 5 27 Oct 2008, 04:31
if y is an integer and y=|x| +x, is y = 0? 1. x<0 2. y Balvinder 4 05 Aug 2007, 23:13
If y is an integer and y = /x/ + x, is y = 0? (1) x < 0 DLMD 10 23 Jan 2005, 15:33
Display posts from previous: Sort by

If y is an integer, y=|x|+x, is y=0? 1)x<0 2)y<1

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.