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Given: y is integer, y = |x| + x
asked : does y = 0 ?
from the question, 0=< y =< infinity; that is, y can range between zero and any positive integer.
because |x| is always positive.
if x is positive then y = 2x
if x is negative then y = 0
x is negative then y = x - x = 0 .. YES y = 0
statement 1 is sufficient (2) y<1
the only possible value for y < 1 is zero because y can never be negative and y is an integer so it can't be some fraction less than 1 like 1/2 or so.
So y in this case has to equal zero [ y = 0 ]
statement 2 is sufficient