Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If y is not equal to 0 and y is not equal to 1, which is [#permalink]

Show Tags

07 Oct 2013, 22:47

You can plug numbers. Based on the question stem, it seems pretty easy to plug and play with some numbers. \(\frac{x}{y}\) or \(\frac{x}{(y+1)}\)

(1) x is not equal to 0 ----> I think from a quick glance, this is not sufficient because we don't know any thing about y. But just for kicks work through the process. Pick numbers: y= 2 , x=2

\(\frac{2}{2}=1\) and \(\frac{2}{2+1}=\frac{2}{3}\) Therefore, \(\frac{x}{y}\) 1 > 2/3 \(\frac{x}{(y+1)}\)

but if we pick y= -2 , x=-2 then \(\frac{-2}{-2}\) = 1 and \(\frac{-2}{-2+1}=\frac{-2}{-1}= 2\), Therefore, \(\frac{x}{y}\) \(1 < 2\) \(\frac{x}{(y+1)}\)

So based on the results, we have two answer, therefore the statement N/S

(2) x > y ----> same thing for this statement. Try using a variation of the same number. Make the both positive and both negative but satisfying the parameters of the statement. Pick numbers: y= 2 , x=4

but if we pick y= -4 , x=-2 then \(\frac{-2}{-4}\) =\(\frac{1}{2}\)and \(\frac{-2}{-4+1}=\frac{-2}{-3}= \frac{2}{3}\), Therefore, \(\frac{x}{y}\) \(.50 < .666\) \(\frac{x}{(y+1)}\)

So we get two different results from picking numbers that satisfied the parameters in Stmt 2. So this is N/S. When you put the two statements together its also I/S. From Stmt 1, we don't if x is positive or negative. That will have a bearing on the results of the numbers as noted above.

I know its been awhile since you made this post, but the time it took me rationalize this correct answer helped me understand why i got the question wrong. Hope this explanation helps someone else where an algebra equation is not intuitive.

gmatclubot

Re: If y is not equal to 0 and y is not equal to 1, which is
[#permalink]
07 Oct 2013, 22:47

http://blog.ryandumlao.com/wp-content/uploads/2016/05/IMG_20130807_232118.jpg The GMAT is the biggest point of worry for most aspiring applicants, and with good reason. It’s another standardized test when most of us...

I recently returned from attending the London Business School Admits Weekend held last week. Let me just say upfront - for those who are planning to apply for the...