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# If y not= 3 and 2x/y is a prime integer greater than 2

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Manager
Joined: 10 Jan 2010
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If y not= 3 and 2x/y is a prime integer greater than 2 [#permalink]  24 Sep 2011, 14:39
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Question Stats:

78% (02:17) correct 21% (01:01) wrong based on 37 sessions
If y not= 3 and 2x/y is a prime integer greater than 2, which of the following must be true?

I. x = y
II. y = 1
III. x and y are prime integers.

(A) None
(B) I only
(C) II only
(D) III only
(E) I and II
[Reveal] Spoiler: OA

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Director
Joined: 01 Feb 2011
Posts: 774
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Kudos [?]: 75 [0], given: 42

Re: NUmber properties [#permalink]  24 Sep 2011, 16:44
given 2x/y is prime and greater than 2.

=> 2x/y could be any of the following
3,5,7....
=> 2x/y is odd and prime (as 2 is the only even prime number and its not in this set)

1. x = y , can't be true

if x=y , 2x/y = 2 which is not odd and prime.

2. y=1. can't be true.

if y=1,2x/y = 2x = even which is not odd & prime.

3. x and y are prime integers, need not be true.

lets say 2x/y = 3 and say y=2 prime
=>x = 6/2 = 3 prime
satisfies the given condition here.

but when 2x/y = 3 and y=5 prime

=> x = 15/2 not prime

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Joined: 20 Dec 2010
Posts: 2058
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Kudos [?]: 815 [0], given: 376

Re: NUmber properties [#permalink]  24 Sep 2011, 17:09
maheshsrini wrote:
If y not= 3 and 2x/y is a prime integer greater than 2, which of the following must
be true?
I. x = y
II. y = 1
III. x and y are prime integers.
(A) None
(B) I only
(C) II only
(D) III only
(E) I and II

I. x = y. Not true AS 2x/y will become 2

II. y = 1
III. x and y are prime integers.
x=26; y=4; Falsifies both II & III, without violating any of the conditions.

Ans: "A"
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Manager
Joined: 10 Jan 2010
Posts: 117
GPA: 4
WE: Programming (Computer Software)
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Kudos [?]: 35 [0], given: 33

Re: NUmber properties [#permalink]  24 Sep 2011, 19:19
I found this problem in the web and did not find the OA. My approach was the same and wanted to confirm the answer.
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Senior Manager
Joined: 11 May 2011
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Re: NUmber properties [#permalink]  24 Sep 2011, 20:42
"A" from my side as well. No option satisfy the criteria.

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Re: NUmber properties   [#permalink] 24 Sep 2011, 20:42
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