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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what

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Director
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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what [#permalink] New post 21 Nov 2007, 11:32
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A
B
C
D
E

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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what is the value of y ?

(1) x + y = 3
(2) x - y = 2
Director
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 [#permalink] New post 21 Nov 2007, 12:07
young_gun wrote:
A, y=3?


I chose A but OA is different.
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 [#permalink] New post 21 Nov 2007, 13:00
Expert's post
D

y = ( x^2 - y^2)/(x-y)=(x+y)(x-y)/(x-y)=x+y ==> x=0; for any y.

1. x + y = 3 ==> y=3 suff
2. x - y = 2 ==> y=-2 suff
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 [#permalink] New post 21 Nov 2007, 13:08
I believe the OA is wrong then..

(x-y)(x+y)/(x-y)=y

y=x+y

x+y=3

y=3

sufficient
Director
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 [#permalink] New post 21 Nov 2007, 15:55
Can someone look at this problem? This is from GMATClub Challenges
http://gmatclub.com/tests/m/02/#q25

Also, is it possible for the variable y to have two different values for 2 cases?
Director
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 [#permalink] New post 21 Nov 2007, 16:27
eyunni wrote:
Can someone look at this problem? This is from GMATClub Challenges
http://gmatclub.com/tests/m/02/#q25

Also, is it possible for the variable y to have two different values for 2 cases?



yes it is possible that you may end up with different values for 2 cases.

In this case it should be D.

1) y = x + y = 3

2) y = x + y => x - y + y = 0 => y = -2
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 [#permalink] New post 21 Nov 2007, 18:41
Late, but D.
Agree with walker (same approach)
  [#permalink] 21 Nov 2007, 18:41
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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what

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