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If you jog half way from A to B at a steady rate of 2miles [#permalink]
24 Feb 2005, 17:44

If you jog half way from A to B at a steady rate of 2miles per hour, how fast would you have to run the rest of the way in order to average 4 miles per hour for the entire trip?

Well speed can not be zero then you won't get a net overall speed of 4 mph. Only way that is possible is if speed is infinite (hence can't be determined)

Answer is 8 miles per hour.
If you go 2 miles per hour halfway through, that means you only ran one mile. Half of 2 is 1.
Ok, you need to catch up and get 4 miles per hour.
You have only 30 minutes to get this done. And you got one mile to get the job done.
The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Very simple, turn that 30 minutes into 15 minutes and voila, 8 miles per hour.
2 miles per hour will get you through the first mile in 30 minutes, going at 8 miles per hour will finish off that last mile in 15 minutes. Entire time would take you 45 minutes to accomplish this run.

This is a no brainer, to me, it's straightforward because I'm a daily runner.

The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Exactly. It would take you 30 minutes for the 2 miles if your average speed is 4 miles per hour. Now look, you are half way of the 2 mile, and how much time have you already used up? 30 minutes! You have no time left for the rest of the trip. You need a miracle to reach the other end instantly, or a infinite speed.

The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Exactly. It would take you 30 minutes for the 2 miles if your average speed is 4 miles per hour. Now look, you are half way of the 2 mile, and how much time have you already used up? 30 minutes! You have no time left for the rest of the trip. You need a miracle to reach the other end instantly, or a infinite speed.

Hey buddy, there's definitely a typo with what the author placed on his message. Don't read it word for word. Read the idea.