If you jog half way from A to B at a steady rate of 2miles : Quant Question Archive [LOCKED]
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# If you jog half way from A to B at a steady rate of 2miles

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Manager
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If you jog half way from A to B at a steady rate of 2miles [#permalink]

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24 Feb 2005, 17:44
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If you jog half way from A to B at a steady rate of 2miles per hour, how fast would you have to run the rest of the way in order to average 4 miles per hour for the entire trip?
VP
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24 Feb 2005, 18:11
hmmm.....if x is half way distance....then total time will be t = x/2
If s is speed for second leg

x/2 = x/s + x/2

x/s = 0....what's wrong with this picture ?

Last edited by banerjeea_98 on 24 Feb 2005, 19:02, edited 1 time in total.
Manager
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24 Feb 2005, 18:28
Well there is a falacy you have to catch it.
:)
VP
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24 Feb 2005, 18:45
anirban16 wrote:
Well there is a falacy you have to catch it.

I wud chose "can't be determined" from the choices, if there were some x/s = 0....can only be possible if X = 0 for this S can be anything.
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24 Feb 2005, 18:52
Yup you are right , the way to frame this word problem is let the total distance be s. and the velocity in the second half be v.
Then we have

(s/2)/2 + (s/2)/v= s/4

Or 1/4 + 1/(2v) = 1/4

Or v = infinite (can't be determined)
VP
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24 Feb 2005, 18:54
i also got the same absurd result.........0 as new speed???????????????????
Director
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24 Feb 2005, 22:09
Agreed, cann't be solved
_________________

Praveen

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25 Feb 2005, 03:47
Yaa even I get the speed as 0.
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25 Feb 2005, 04:55
We request not to be subjected to such wastage of time. ETS wouldn't ask such questions.
Manager
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25 Feb 2005, 07:55
there is no answer correct? it would be dependent upon the total distance of the trip which isnt given in the question
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25 Feb 2005, 12:06
Well speed can not be zero then you won't get a net overall speed of 4 mph. Only way that is possible is if speed is infinite (hence can't be determined)
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25 Feb 2005, 22:39
Answer is 8 miles per hour.
If you go 2 miles per hour halfway through, that means you only ran one mile. Half of 2 is 1.
Ok, you need to catch up and get 4 miles per hour.
You have only 30 minutes to get this done. And you got one mile to get the job done.
The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Very simple, turn that 30 minutes into 15 minutes and voila, 8 miles per hour.
2 miles per hour will get you through the first mile in 30 minutes, going at 8 miles per hour will finish off that last mile in 15 minutes. Entire time would take you 45 minutes to accomplish this run.

This is a no brainer, to me, it's straightforward because I'm a daily runner.
SVP
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25 Feb 2005, 22:57
supraboy888 wrote:
The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Exactly. It would take you 30 minutes for the 2 miles if your average speed is 4 miles per hour. Now look, you are half way of the 2 mile, and how much time have you already used up? 30 minutes! You have no time left for the rest of the trip. You need a miracle to reach the other end instantly, or a infinite speed.
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25 Feb 2005, 23:34
averaging out speed.
(s+2miles)/2=4 (you can do this way as distances are same for both the speeds).
s=6mph
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26 Feb 2005, 00:24
700Plus wrote:
averaging out speed.
(s+2miles)/2=4 (you can do this way as distances are same for both the speeds).
s=6mph

Is it 6mph or 8mph? My first calculation was 6mph, but I changed my mind.
Show me the light at the end of the tunnel. I'm bad with formulas.
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26 Feb 2005, 00:26
HongHu wrote:
supraboy888 wrote:
The entire trip is 2 miles, it would take 30 minutes if you ran 4 miles per hour.

Exactly. It would take you 30 minutes for the 2 miles if your average speed is 4 miles per hour. Now look, you are half way of the 2 mile, and how much time have you already used up? 30 minutes! You have no time left for the rest of the trip. You need a miracle to reach the other end instantly, or a infinite speed.

Hey buddy, there's definitely a typo with what the author placed on his message. Don't read it word for word. Read the idea.
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26 Feb 2005, 07:53
I understand your point. But there isn't a typo there. The basic idea is wrong.
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27 Feb 2005, 17:13
HongHu wrote:
I understand your point. But there isn't a typo there. The basic idea is wrong.

If the basic idea is wrong, then there is no definitive answer to this question. This question should be taken off this board.
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28 Feb 2005, 08:09
I agree. It is not a GMAT type question. It's kind of a brain teaser.
Director
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28 Feb 2005, 13:10
Very good one. May not be GMAT question, but still stimulates the mind.
Keep them coming.
28 Feb 2005, 13:10

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