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If yz not equal to 0, is 0<y<1 ? (1) y< 1/y (2) y =

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If yz not equal to 0, is 0<y<1 ? (1) y< 1/y (2) y = [#permalink] New post 02 Oct 2011, 13:59
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A
B
C
D
E

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If yz not equal to 0, is 0<y<1 ?

(1) y< 1/y
(2) y=z^2
[Reveal] Spoiler: OA

Last edited by shashankp27 on 04 Oct 2011, 10:52, edited 1 time in total.
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Re: yz [#permalink] New post 02 Oct 2011, 16:08
shashankp27 wrote:
If yz not equal to 0, is 0<y<1 ?

(1) y< 1/y
(2) y=z^2



My answer is A.

Dont find any relevance to 2nd statement.
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Re: yz [#permalink] New post 02 Oct 2011, 21:06
IMO E

Stmt A: the statement satisfies when y is negative or between 0 and 1. Not sufficient
Stmt B: Nothing is known about Z. Not Sufficient

Combining the statement also not suffient to conclude.
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Re: yz [#permalink] New post 02 Oct 2011, 21:55
divyakatas wrote:
IMO E

Stmt A: the statement satisfies when y is negative or between 0 and 1. Not sufficient
Stmt B: Nothing is known about Z. Not Sufficient

Combining the statement also not suffient to conclude.



i think from 2nd stmt, we know y is not negative. so it shud be between 0 and 1.
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Re: yz [#permalink] New post 02 Oct 2011, 22:49
1)

y < -1, or 0 < y < 1

NS

2)

y = z^2

y > 0

NS

1+2)

Given y < -1 or 0 < y < 1
and y > 0

then, 0 < y < 1

C
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Re: yz [#permalink] New post 03 Oct 2011, 00:12
(1)
y<1/y

y^2<1, y>0
y^2>1, y<0

0<y<1, y<-1
So, we could not say whether 0<y<1.

(2)
y=z^2
This means that y>0 (since yz is not 0), but we do not know whether y>1 or not.

(1) and (2) together
y<-1, 0<y<1 and y>0
0<y<1

So, tho statements together are sufficient.
The answer is (C)
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Re: yz   [#permalink] 03 Oct 2011, 00:12
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