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If (z+3)/(z-1) + (z+1)/(z-3)=2, then z=

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Joined: 06 Sep 2013
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If (z+3)/(z-1) + (z+1)/(z-3)=2, then z= [#permalink] New post 11 Oct 2013, 16:10
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

65% (02:03) correct 35% (01:02) wrong based on 52 sessions
If \frac{z+3}{z-1}+\frac{z+1}{z-3} = 2, then z=

(A) 2
(B) 1
(C) -1
(D) -2
(E) -3
[Reveal] Spoiler: OA

Last edited by jlgdr on 13 Oct 2013, 04:01, edited 3 times in total.
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Re: If (z+3)/(z-1) + (z+1)/(z-3)=2, then z= [#permalink] New post 11 Oct 2013, 16:29
Expert's post
jlgdr wrote:
If \frac{z+3}{z-1}+\frac{z+1}{z-3} = 2, then z=

(A) 2
(B) 1
(C) -1
(D) -2
(E) -3


I would solve this question by substituting the options but below is an algebraic approach if interested:

\frac{z+3}{z-1}+\frac{z+1}{z-3} = 2;

\frac{z^2-9+z^2-1}{(z-1)(z-3)}= 2;

2z^2-10=2z^2-8z+6;

8z=16;

z=2.

Answer: A.
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SVP
SVP
User avatar
Joined: 06 Sep 2013
Posts: 1667
Location: United States
Concentration: Finance
GMAT 1: 710 Q48 V39
WE: Corporate Finance (Investment Banking)
Followers: 13

Kudos [?]: 166 [0], given: 275

GMAT ToolKit User
Re: If (z+3)/(z-1) + (z+1)/(z-3)=2, then z= [#permalink] New post 11 Oct 2013, 16:49
Bunuel wrote:
jlgdr wrote:
If \frac{z+3}{z-1}+\frac{z+1}{z-3} = 2, then z=

(A) 2
(B) 1
(C) -1
(D) -2
(E) -3


I would solve this question by substituting the options but below is an algebraic approach if interested:

\frac{z+3}{z-1}+\frac{z+1}{z-3} = 2;

\frac{z^2-9+z^2-1}{(z-1)(z-3)}= 2;

2z^2-10=2z^2-8z+6;

8z=16;

z=2.

Answer: A.


I agree, best approach is to sustitute. Now next question would be? Do we have a way to do a fast check and see which value to substitute first?
1 KUDOS received
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Joined: 24 Apr 2013
Posts: 20
Location: India
Concentration: Strategy, Marketing
GMAT Date: 10-30-2013
WE: Engineering (Other)
Followers: 0

Kudos [?]: 1 [1] , given: 44

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Re: If (z+3)/(z-1) + (z+1)/(z-3)=2, then z= [#permalink] New post 12 Oct 2013, 21:16
1
This post received
KUDOS
jlgdr wrote:
Bunuel wrote:
jlgdr wrote:
If \frac{z+3}{z-1}+\frac{z+1}{z-3} = 2, then z=

(A) 2
(B) 1
(C) -1
(D) -2
(E) -3


I would solve this question by substituting the options but below is an algebraic approach if interested:

\frac{z+3}{z-1}+\frac{z+1}{z-3} = 2;

\frac{z^2-9+z^2-1}{(z-1)(z-3)}= 2;

2z^2-10=2z^2-8z+6;

8z=16;

z=2.

Answer: A.


I agree, best approach is to sustitute. Now next question would be? Do we have a way to do a fast check and see which value to substitute first?



I agree...OA is A someone kindly change the OA in the question...
SVP
SVP
User avatar
Joined: 06 Sep 2013
Posts: 1667
Location: United States
Concentration: Finance
GMAT 1: 710 Q48 V39
WE: Corporate Finance (Investment Banking)
Followers: 13

Kudos [?]: 166 [0], given: 275

GMAT ToolKit User
Re: If (z+3)/(z-1) + (z+1)/(z-3)=2, then z= [#permalink] New post 13 Oct 2013, 04:02
OA has been changed

Cheers

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Re: If (z+3)/(z-1) + (z+1)/(z-3)=2, then z=   [#permalink] 13 Oct 2013, 04:02
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