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Re: Tricky DS - Factors based problem [#permalink]
21 Jun 2011, 00:01

A indeed.

Statement 1: Z can be 24,25,26,27,28, having factors of respectively: 2^3(3), 5^2, 2(13), 3^3, 7(2^2),

as you can see no value for Z has more than 2 different integer factors.

Statement 2: insufficient. Z could be anything. Z could be 15, having 2 different factors. But it could alsof be 105 having 3 different factors (3,5,7).

Re: Tricky DS - Factors based problem [#permalink]
24 Jun 2011, 02:20

23 < z < 29 No prime numbers in the range above So all have more than 2 factors Sufficient Some odd numbers are prime some are non prime so Answer is A

gmatclubot

Re: Tricky DS - Factors based problem
[#permalink]
24 Jun 2011, 02:20