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If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4

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If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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New post 05 May 2012, 00:44
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If zt < -3, is z < 4 ?

(1) z < 9
(2) t < -4
[Reveal] Spoiler: OA
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Re: If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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New post 05 May 2012, 00:52
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naveenhv wrote:
If zt < -3, is z < 4 ?

(1) z < 9
(2) t < -4


Number picking would probably be the most efficient way to attack this problem. Even when we consider both statements together we can easily find two sets of numbers which give us different answers to the question whether z<4:

If z=5 and t=-5 (zt=-25<-3) the answer is NO;
If z=1 and t=-5 (zt=-5<-3) the answer is YES.

Answer: E.
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Re: If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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New post 06 May 2012, 15:30
Vote for E

i did it this way


(A) when Z < 9

if (Z = 8 and t = -1/2)

zt < -3 = true

Z < 4 (NO)


if (Z = 2 and t = -1/2)

zt < -3 = true

Z < 4 (Yes)

Data not sufficient

----------------------------

(B) t < -4

if (Z = 8 and t = -5)

zt < -3 = true

Z < 4 (NO)


if (Z = 2 and t = -5)

zt < -3 = true

Z < 4 (Yes)

Data not sufficient

-----------------------------

(C) combine when Z < 9 and t < -4

if (Z = 8 and t = -5)

zt < -3 = true

Z < 4 (NO)


if (Z = 2 and t = -5)

zt < -3 = true

Z < 4 (Yes)

Data not sufficient

there for E
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If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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New post 21 Jun 2014, 00:18
Bunuel wrote:
naveenhv wrote:
If zt < -3, is z < 4 ?

(1) z < 9
(2) t < -4


Number picking would probably be the most efficient way to attack this problem. Even when we consider both statements together we can easily find two sets of numbers which give us different answers to the question whether z<4:

If z=5 and t=-5 (zt=-25<-3) the answer is NO;
If z=1 and t=-5 (zt=-5<-3) the answer is YES.

Answer: E.


Hi Bunuel and other experts,

When you do this(number picking) it seems so simply! However, number picking is my Achilles' Heel. It is just so frustratingly difficult for me to come up with right numbers.

When I micro-analyze my thinking process while I try to come up with right values to show counter examples this is what I see: I first need to ensure z <9 and then make sure that t < -4 and then ensure that zt< -3 with the aim of getting a NO for z<4. Even though I am using 'then' after every decision, the fact is- to generate right values, you essentially need to make these 4 decisions simultaneously. I simply dont know how I can do this in 20-30 seconds without befuddling my short term memory apparatus. I am saying 20-30 secs as in most of the hard questions you will have to rule out st-A, st-B and A+B. thus you will make 5-6 such decisions for every question.

When I solve such questions I am either totally flustered or take more than 4 mins. Are there efficient ways to do this and which will work for most of the hard problems (inequality, modulus, reciprocal, neg/pos and their combination) etc..in less than 2-3 mins?
Thanks!
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If zt < -3, is z < 4 [#permalink]

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New post 25 Oct 2014, 09:55
If zt < -3, is z < 4 ?
(1) z < 9
(2) t < -4
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Re: If zt < -3, is z < 4 [#permalink]

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New post 25 Oct 2014, 19:54
ajaym28 wrote:
If zt < -3, is z < 4 ?
(1) z < 9
(2) t < -4


zt < -3 implies either z>0 and t<0 or z<0 and t>0
(1) we ain't told anything abt t... Also, z can be 2 or 4 producing a Y/N cases
(2) at least we know t is <0; but we dont know whether z>4 or <4.

Both alone insufff.

Taken together, tsst: z=2, t=-5 we get zt = -10 (<-3)
Response to stem is Yes, z < 4

Also, take z=4 and t=-5 we get zt = -20 (<-3)
Response is No z is not < 4.

So, E should be OA.
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Re: If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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New post 26 Oct 2014, 06:28
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Re: If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4 [#permalink]

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Re: If zt < -3, is z < 4 ? (1) z < 9 (2) t < -4   [#permalink] 14 Aug 2016, 11:00
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