lylya4 wrote:

zy < xy < 0, => xz > 0

The question: |x - z| + |x| = |z| => with xz > 0, this is only true if (x-z)x < 0

(1) z < x (insuff, don't know x +ve or -ve)

(2) y > 0 => x,z < 0 (insuff, don't know x - z is +-ve)

(1)&(2) suff

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Wrong!

|x - z| + |x| = |z| can be written as |x - z| | = |z! - !x!

So the question asks us whether X and Z are of the same sign?

1) z < x

It means that EITHER Y is smth negative and Z and X are positive

OR

Y is smth negative and Z and X are negative. Suff - that is exactly what we are trying to understand - whether X and Z are of the same sign?

(2) y > 0

Read above. That tells us that X and Z are of the same sign. Sufficient.

OA is D