Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 05 May 2015, 04:57

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If zy < xy < 0, is |x-z| + |x| = |z|? (1) z<x>0

Author Message
TAGS:
Intern
Joined: 17 Apr 2007
Posts: 24
Followers: 0

Kudos [?]: 2 [0], given: 0

If zy < xy < 0, is |x-z| + |x| = |z|? (1) z<x>0 [#permalink]  13 May 2007, 11:40
If zy < xy < 0, is |x-z| + |x| = |z|?

(1) z<x>0

OA is D
Intern
Joined: 17 Apr 2007
Posts: 24
Followers: 0

Kudos [?]: 2 [0], given: 0

oops...should be

(1) z is less than x
(2) y is greater than 0

Last edited by kookoo4tofu on 13 May 2007, 11:42, edited 1 time in total.
Senior Manager
Joined: 03 May 2007
Posts: 272
Followers: 1

Kudos [?]: 7 [0], given: 0

can you post the rest of the question?
VP
Joined: 08 Jun 2005
Posts: 1147
Followers: 6

Kudos [?]: 128 [0], given: 0

|x-z| + |x| = |z|

can be rewritten as

|x-z| = |z|-|x|

Statement 1

whenever statement 1 is true |z|-|x| is negative.

|x-z| can never be negative

so we can say for sure that when z is less then x , the inequality is false.

sufficient

Statement 2

when y is grater then 0 then x,z have to be negative.

if x,z are negative and y is positive

when zy < xy < 0

then z<x

same info & logic as statement 1

sufficient

Last edited by KillerSquirrel on 13 May 2007, 12:39, edited 1 time in total.
SVP
Joined: 01 May 2006
Posts: 1805
Followers: 8

Kudos [?]: 99 [0], given: 0

My answer and other ones are here : http://www.gmatclub.com/phpbb/viewtopic.php?t=44909
Manager
Joined: 13 Feb 2007
Posts: 63
Followers: 1

Kudos [?]: 1 [0], given: 0

i. is not sufficient. you above KillerSquirrel have illustrated a case in which the questioned equation results in false. I'll illustrate one in which the questioned equation results in true: z = -3, x = -2, y = 1. | x - z | =
| z | - | x |.......So in this case, | -2 - (- 3) | = | -3 | - | - 2|, 1=1. So, of course, if we have one answer in which we get true and one in which we get false, statement i is insufficient. I get E as the answer then. Because you spotted that statement ii is equivalent to i. I didn't catch that part. I thought at first B was the answer.
SVP
Joined: 01 May 2006
Posts: 1805
Followers: 8

Kudos [?]: 99 [0], given: 0

ethan_casta wrote:
i. is not sufficient. you above KillerSquirrel have illustrated a case in which the questioned equation results in false. I'll illustrate one in which the questioned equation results in true: z = -3, x = -2, y = 1. | x - z | =
| z | - | x |.......So in this case, | -2 - (- 3) | = | -3 | - | - 2|, 1=1. So, of course, if we have one answer in which we get true and one in which we get false, statement i is insufficient. I get E as the answer then. Because you spotted that statement ii is equivalent to i. I didn't catch that part. I thought at first B was the answer.

Actually, it's always true ... For statment (1) & (2)... Have a look at my link
VP
Joined: 08 Jun 2005
Posts: 1147
Followers: 6

Kudos [?]: 128 [0], given: 0

ethan_casta wrote:
i. is not sufficient. you above KillerSquirrel have illustrated a case in which the questioned equation results in false. I'll illustrate one in which the questioned equation results in true: z = -3, x = -2, y = 1. | x - z | =
| z | - | x |.......So in this case, | -2 - (- 3) | = | -3 | - | - 2|, 1=1. So, of course, if we have one answer in which we get true and one in which we get false, statement i is insufficient. I get E as the answer then. Because you spotted that statement ii is equivalent to i. I didn't catch that part. I thought at first B was the answer.

yes ! you are right my logic is "non sequitur"
Director
Joined: 26 Feb 2006
Posts: 905
Followers: 4

Kudos [?]: 52 [0], given: 0

Re: GMATPrep: abs [#permalink]  13 May 2007, 13:51
kookoo4tofu wrote:
If zy < xy < 0, is |x-z| + |x| = |z|?

(1) z is less than x
(2) y is greater than 0
OA is D

from i, if z is less than x, then x and z are -ve and y is +ve.. suff
from ii, if y is +ve, then again x and z are -ve and it is also sufficient.

So D.
Manager
Joined: 13 Feb 2007
Posts: 63
Followers: 1

Kudos [?]: 1 [0], given: 0

Abs value [#permalink]  13 May 2007, 14:07
Himalayan, the question is not that simple unfortunately.
Manager
Joined: 18 Apr 2007
Posts: 121
Followers: 1

Kudos [?]: 5 [0], given: 0

zy<xy<0...This means that z<x<0>0 and z>x>0 if y<0. In other words, both z and x have to be the same sign.

[1] z<x>0 Both z and x are negative - sufficient.

[2] kookoo4tofu wrote "y is greater than 0", but I believe the correct stmt is y<0. Using this stmt, both z and x are positive and therefore sufficient.

Manager
Joined: 13 Feb 2007
Posts: 63
Followers: 1

Kudos [?]: 1 [0], given: 0

Abs value [#permalink]  13 May 2007, 14:24
didn't you guys see that two cases have been advanced in which statement i produces a result of true and also a result of false? that disproves your claim.
Intern
Joined: 17 Apr 2007
Posts: 24
Followers: 0

Kudos [?]: 2 [0], given: 0

i checked the question again and statement 2 does say "y greater than zero"
Director
Joined: 26 Feb 2006
Posts: 905
Followers: 4

Kudos [?]: 52 [0], given: 0

Re: Abs value [#permalink]  14 May 2007, 17:48
ethan_casta wrote:
Himalayan, the question is not that simple unfortunately.

you are right. i just laid down what i had in a quick calculation in my mind.
Re: Abs value   [#permalink] 14 May 2007, 17:48
Similar topics Replies Last post
Similar
Topics:
1 If zy < xy < 0 is |x-z| + |x| = |z| 5 17 Jan 2010, 10:42
If zy < xy < 0, is |x-z| + |x| = |z|? (1) z<x (2) 9 31 Jul 2008, 05:24
If zy<xy<0, is |x-z| + |x| = |z|? 1: z<x 2: y>0 5 29 Jul 2007, 13:43
2 ZY<XY<0 is |X-Z| + |x| = |Z| 14 25 Apr 2007, 03:18
If zy<xy<0 is |x-z| + |x| = |z|? 1. z<x>0 2. 5 02 Feb 2007, 18:01
Display posts from previous: Sort by