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# In 1966 the operative mortality rate in open heart surgery

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Manager
Joined: 25 Mar 2006
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Location: Stonybrook Univ
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In 1966 the operative mortality rate in open heart surgery [#permalink]  08 Apr 2006, 15:29
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In 1966 the operative mortality rate in open heart surgery at a certain hospital was 8.1 per 100 cases. By 1974 the rate had declined to 4.8 per 100 cases. If the rate declined by 20% from 1973 to 1974, by approximately what percent did it decline from 1966 to 1973.

a) 6
b) 21
c) 25
d) 41
e) 49

no guessing

Last edited by NTLancer on 08 Apr 2006, 15:50, edited 1 time in total.
Manager
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[#permalink]  08 Apr 2006, 15:46
Answer is C

I am assuming you meant 1966 in the first sentence. First find the 1973 rate by backsolving with the 20% change => .2=(x-4.8)/x ---> x=6. Now solve for the change from 1966 to 1973 => x=(6-8.1)/8.1 ---->x=.25 or 25%
Manager
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Re: PS open heart surgery [#permalink]  08 Apr 2006, 15:48
NTLancer wrote:
In 1996 the operative mortality rate in open heart surgery at a certain hospital was 8.1 per 100 cases. By 1974 the rate had declined to 4.8 per 100 cases. If the rate declined by 20% from 1973 to 1974, by approximately what percent did it decline from 1966 to 1973.

a) 6
b) 21
c) 25
d) 41
e) 49

no guessing

Answer C;

Find what it was in 1973 i.e. x0.8=4.8 whereby x=6.0
Decline from 1966 to 1973 = 8.1 -6.0 =2.1

Percent decline= 2.1/8.1 *100= 25 approximately
Manager
Joined: 25 Mar 2006
Posts: 132
Location: Stonybrook Univ
Followers: 1

Kudos [?]: 1 [0], given: 0

[#permalink]  08 Apr 2006, 15:50
yep there was a typo sorry about that

OA is C good job everyone
[#permalink] 08 Apr 2006, 15:50
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# In 1966 the operative mortality rate in open heart surgery

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