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# In 1985 a company sold a brand of shoes to retailers for a

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Intern
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In 1985 a company sold a brand of shoes to retailers for a [#permalink]

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12 Jul 2007, 18:48
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 30 percent. If the company's revenue from the sales of the shoes in1986 was 3million, what was the approximate revenue from the sale of the shoes in 1985?

A) 2.4M
B) 2.9M
C) 3M
D) 3.1M
E) 3.6M
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12 Jul 2007, 19:23
Let's assume the number of pair sold in 1985 is X. In 1986 the pair deceased by 20% so the number of pair sold will be 0.8X. Let's assume the cost per pair is Y in 1985. In 1986 it increased 30%, therefore the cost in 1986 is 1.3Y.
The revenue for 1985 is X*Y
and the revenue for 1986 is 0.8X*1.3Y, since we know from the question that 0.8X*1.3Y=3M, therefore we can find out XY=3/(0.8*1.3), which is approximately 2.9M. So the answer will be B
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Re: Parts of Numbers Q4 [#permalink]

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12 Jul 2007, 19:23
700dreamer wrote:
In 1985 a company sold a brand of shoes to retailers for a fixed price per pair. In 1986 the number of pairs of the shoes that the company sold to retailers decreased by 20 percent, while the price per pair increased by 30 percent. If the company's revenue from the sales of the shoes in1986 was 3million, what was the approximate revenue from the sale of the shoes in 1985?

A) 2.4M
B) 2.9M
C) 3M
D) 3.1M
E) 3.6M

B
Let s = # of shoes
(.80s)(1.3)=3,000,000 ... Solving for s will give you the # of shoes sold in 85'
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12 Jul 2007, 20:13
= 3/(0.8 * 1.3) ~ 2.9

So B........
12 Jul 2007, 20:13
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