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can it solve through chemical mixture strategy in mgmat guide

Please post answer choices for PS problems. Also make sure you don't reword the questions you post.

As for the question: There are 10% of water in 70L --> there are 7L of waters; After x liters of water is added amount of water becomes (7+x) liters, which on the other hand is 1/4th (25%) of new (70+x) liters of mixture: 7+x=1/4*(70+x) --> 28+4x=70+x --> x=14.

The formula discussed can be used in a ton of questions including this one. Once you get used to this method of solving, you will pretty much be solving this question orally. After going through the post, see if this makes sense:

Solution 1 has 10% water. Solution 2 has 100% water. (You are mixing solution 1 with pure water.) Mixture should have 25% water. w1/w2 = (100 – 25)/(25 – 10) = 75/15 = 5/1 So volume of solution 1 : volume of water = 5:1 Solution 1 is 70 litres, so 14 litres of water must be added. _________________

Re: In 70 liters of a mixture of milk and water, the quantity of [#permalink]
26 Jan 2012, 05:25

In 70 ltr solution we have 63 ltr of milk and 7 ltr of water now we are adding water but the amount of milk remains constant so (70+x)*75/100 = 63 where x is the amount of water added on solving x=14

Re: In 70 liters of a mixture of milk and water, the quantity of [#permalink]
17 Apr 2012, 10:44

1

This post received KUDOS

Expert's post

ENAFEX wrote:

Karishma,

I found your post on mixtures very useful. I am stuck in the above problem. Please help I solved w1/w2 to be (90-25)/(25-10) = 65/15.

Can you please explain how you got 75/15?

The two mixtures are: a 10% water solution, only water (which is 100% water) We combine them to get 25% water solution. Therefore, it is actually (100 - 25)/(25 - 10) and not (90 - 25)/(25 - 10) _________________

Re: In 70 liters of a mixture of milk and water, the quantity of [#permalink]
13 Oct 2013, 14:55

Hello from the GMAT Club BumpBot!

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