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In a acertain company, the ratio of the numer of manager to

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In a acertain company, the ratio of the numer of manager to [#permalink]

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In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25
[Reveal] Spoiler: OA
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Re: Ratio PS Manager Production line worker [#permalink]

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Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


Let there be x managers. Then the number of workers is 72/5 * x
With extra workers the ratio becomes 5 to 74, therefore :

\(\frac{(72/5)x + 8}{x}=\frac{74}{5}\)

\(72x + 40 = 74x\)

\(x = 20\)

Answer is (d)
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Re: Ratio PS Manager Production line worker [#permalink]

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Gacarva wrote:
In a acertain company, the ratio of the numer of manager to the number of production-line workers is 5 to 72. If 8 additional Production-line workers were to be hired, the ratio of the number of managers to the number of production-line workers would be 5 to 74. How many managers does the company have?

A. 5
B. 10
C. 15
D. 20
E. 25


You can solve this problem the way discussed above or try the following:

Given: \(\frac{m}{w}=\frac{5x}{72x}\), now 8 workers were hired and new ratio became \(\frac{m}{w+8}=\frac{5x}{74x}=\frac{5x}{72x+2x}\), notice that nominator didn't change, so increase by 2 parts in denominator corresponds to increase by 8 workers (2 parts correspond to 8 workers = 4 times or in another words 2x=8 --> x=4), so 5 parts in nominator correspond to 5*4=20 managers.

Answer: D.
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Re: Ratio PS Manager Production line worker [#permalink]

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New post 21 Sep 2010, 06:08
Thank you all, I will work on problems like this one and follow your advice.
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company [#permalink]

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let manager=m , and worker =w
m/w=5/72
=5w=72m.....1
m/w+8=5/74
5w+40=74m...........2
by solving the equations.....we find m=20
so ans is D
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Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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New post 05 Feb 2012, 03:22
Ans is D
m/w = 5/72 and m/w+8 = 5/74
where m is no of managers and w is the no of production workers. On solving we get the answer as m=20
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Re: In a acertain company, the ratio of the numer of manager to [#permalink]

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Re: In a acertain company, the ratio of the numer of manager to   [#permalink] 08 Jul 2016, 23:46
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