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let there be 100 combatants, of which
1) 30 did not lost an eye; therefore, 70 did lost one, of which
2) 20 did not lost an ear; therefore, 50 did lost one, of which
3) 25 did not lost an arm; therefore, 25 did lost one, of which
4) 15 did not lost a leg; therefore, 10 did lost one
Finally, these 10 are the most unlucky ones.
I do not see, however, why this number is minimal. It should be the only solution, no?
BTW, is it possible to calculate the number of people who lost nothing?
In a battle 70% of the combatants lost an eye, 80% an year,75% an arm,85% a leg,x% lost all the 4 limbs. The minimum value of X is
1. 10 2. 12 3. 15 4. None of these
The answer is 10 but how ??
It's OK, khurman... Look, if a% of combatants lost something A, and b% of combatants lost something (et's call it B), then AT LEAST (a + b - 100)% of combatants lost both A and B.
Thus, we get that at least 50% = 70 + 80 - 100 lost both an eye and an ear, at least 25% = 50% + 75% - 100% lost an eye, an ear, and an arm, and at least 10% = 25% + 85% - 100% lost an eye, an ear, an arm, and a leg..!