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Manager
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In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink]
 19 Mar 2008, 23:59
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In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?
Please advise the best way to solve this problem
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Manager
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85%
leg is subset of 4 limbs ( i suppose ^^). So those lost 4 limbs sure lost leg
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CEO
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az780 wrote: In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is? terrible  it is a strange question... So, 70% an eye, 80% an ear, 75% an arm, 85% a leg. 1. an eye and and an ear: p=[50%,70%] 2. (an eye and and an ear) and an arm: p=[25%,70%] 3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%] Therefore, min: 10%, max: 70%
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walker wrote: az780 wrote: In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is? terrible it is a strange question... So, 70% an eye, 80% an ear, 75% an arm, 85% a leg. 1. an eye and and an ear: p=[50%,70%] 2. (an eye and and an ear) and an arm: p=[25%,70%] 3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%] Therefore, min: 10%, max: 70% This is really funny problem. I can not stand when I read it.  Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also 
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sondenso wrote:  1. Let we have two attributes: A and B. 2. Let a% of people have A and b% of people have B. 3. we will try to find max and min ab% (the percentage of people that have two attributes) I'll try to draw: the maximum configuration: | aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100% | bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100% max=min(a,b) the minimum configuration: |aaaaaaaaaaa aaaaaaaaaaaaaaaaaaaaaaa------------------| 100% |--------------- bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100% min=b-(100-a)=a+b-100. if min<0 then min have to be 0 for example, a=75%, b=87% max=min(75%,87%)=75% min=87%-(100%-75%)=62%
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walker wrote: sondenso wrote: 1. Let we have two attributes: A and B. 2. Let a% of people have A and b% of people have B. 3. we will try to find max and min ab% (the percentage of people that have two attributes) I'll try to draw: the maximum configuration: | aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100% | bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100% max=min(a,b) the minimum configuration: |aaaaaaaaaaa aaaaaaaaaaaaaaaaaaaaaaa------------------| 100% |--------------- bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100% min=b-(100-a)=a+b-100. if min<0 then min have to be 0 for example, a=75%, b=87% max=min(75%,87%)=75% min=87%-(100%-75%)=62% Thank you Walker, you are great! 
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