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In a certain animal population, for each of the first 3

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In a certain animal population, for each of the first 3 [#permalink] New post 07 Jun 2003, 12:06
. In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is . For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
(A) 140
(B) 146
(C) 152
(D) 162
(E) 170
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 [#permalink] New post 07 Jun 2003, 13:07
dude, plz complete the first sentence
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 [#permalink] New post 07 Jun 2003, 13:14
In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10 . For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?

Sorry everybody, Uncle Stoylar, its time to take alook!
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Re: HARD QUESTION [#permalink] New post 07 Jun 2003, 17:00
:-D :-D :-D :-D
Curly05 wrote:
. In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is . For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
(A) 140
(B) 146
(C) 152
(D) 162
(E) 170
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 [#permalink] New post 07 Jun 2003, 17:05
Month 1 : Dead = 1/10*200 =20
Month 2 : Dead = 1/10*(200-20)=18
Month 3 : Dead = 1/10*(200-20-18)=16

Total Dead = 54 => Alive = 200-54=146
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Bullshit [#permalink] New post 07 Jun 2003, 17:29
It's really alot easier than I thought. Every chance they have is a probability question and is very similar like the official guide states.

9/10, 9/10 the 2nd, and 9/10 the third time.
Independent events, baby :-D :-D :-D

ETS works in patterns, exploit it.

But, if your like Tzolin, you got it baby!

thanks :no
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Re: Bullshit [#permalink] New post 07 Jun 2003, 18:15
Expert's post
Curly05 wrote:
It's really alot easier than I thought. Every chance they have is a probability question and is very similar like the official guide states.

9/10, 9/10 the 2nd, and 9/10 the third time.
Independent events, baby :-D :-D :-D

ETS works in patterns, exploit it.

But, if your like Tzolin, you got it baby!

thanks :no



They probably work in patterns, but I would not put all my hope into that. :pray
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 [#permalink] New post 14 Mar 2006, 21:49
First month: 9/10*200 = 180 will survive
Second month: 9/10*180 = 162 will survive
Third month: 9/10*162 = 146 will survive
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Re: HARD QUESTION [#permalink] New post 15 Mar 2006, 17:54
Curly05 wrote:
:-D :-D :-D :-D
Curly05 wrote:
. In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is . For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?
(A) 140
(B) 146
(C) 152
(D) 162
(E) 170


:roll: :roll: :roll: :roll: :P :P :P :P :P
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 [#permalink] New post 15 Mar 2006, 19:00
The question is, how many would be expected to survive the 3 months?

The probability for survival each month is 9/10; thus, the probability for surviving 3 months is:

9/10 * 9/10 * 9/10 = 9^3/10^3

Multiply that with the original population of 200 and you get approx. 146.

Answer (B)
  [#permalink] 15 Mar 2006, 19:00
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