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In a certain animal population, for each of the first 3 mont [#permalink]

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20 Aug 2008, 01:52

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In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life?

Re: In a certain animal population, for each of the first 3 mont [#permalink]

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20 Aug 2008, 02:50

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My take, P(animal dying during first 3 months) = P(dying in M1) + P(dying in M2) + P(dying in M3) = (1/10) + (9/10)*(1/10) + (9/10)*(9/10)*(1/10) = 271/1000

P(animal surviving the first 3 months) = 729/1000

No Of animals surviving (approx) = (729/1000) * 200 = 146

Re: In a certain animal population, for each of the first 3 mont [#permalink]

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20 Aug 2008, 04:52

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Ginc wrote:

In a certain animal population for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, aprroximately how many would be expected to survive the first 3 month of life? a)140 b)146 c)152 d)162 e)170

How would you solve this? Thanks

Number of newborns that can die in first month = 1/10 * 200 = 20

Survived = 180

Number of newborns that can die in second month = 1/10 * 180 = 18

Survived = 162

Number of newborns that can die in third month = 1/10 * 162 = 16

In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? A/ 140 B/ 146 C/ 152 D/ 162 E/ 170

The probability of survival for each of the first 3 months of life is 1-1/10=9/10, so of 200 newborn 200*9/10*9/10*9/10=~146 is expected to survive.

Re: In a certain animal population, for each of the first 3 mont [#permalink]

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17 Aug 2014, 07:26

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Re: In a certain animal population, for each of the first 3 mont [#permalink]

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31 Oct 2015, 10:58

Hello from the GMAT Club BumpBot!

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Re: In a certain animal population, for each of the first 3 mont [#permalink]

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01 Nov 2015, 23:00

Bunuel wrote:

Madelaine88 wrote:

In a certain animal population, for each of the first 3 months of life, the probability that an animal will die during that month is 1/10. For a group of 200 newborn members of the population, approximately how many would be expected to survive the first 3 months of life? A/ 140 B/ 146 C/ 152 D/ 162 E/ 170

The probability of survival for each of the first 3 months of life is 1-1/10=9/10, so of 200 newborn 200*9/10*9/10*9/10=~146 is expected to survive.

Answer: B.

Hi Bunuel,

If probability of survival can be calculated with 3 times 9/10 , the same can apply to probability of death for 3 months. But the answers would be different.

200*1/10*1/10*1/10 = 0.2.

Can you explain why this approach does not work ? Thanks.

gmatclubot

Re: In a certain animal population, for each of the first 3 mont
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01 Nov 2015, 23:00

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