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in a certain city 80% of the houses have cables and 60% have VCR. what

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in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 04:47
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in a certain city 80% of the houses have cables and 60% have VCR. what is the range of houses that have both cables and a VCR, if there are 150,000 houses:(IN THOUSENDS)

1. 30-60
2. 30-90
3. 60-90
4. 60-150
5. 90-150

I used a table solving for NO CABLES/NO VCR=0 and then VCR/NO CABLES=0 to recieve the anser which seems correct.

is som1 can suggest a quicker method?

kind regards
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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The highest range can be the # of people who have both Cables and VCR, which means 60% of people have cables, and VCR too.

So 60% of people = 60/100 * 150000 = 90000

Then again, the least overlap can be like :

80% + 60% - 100% = 40%

40% of 150000 = 40/100 * 150000 = 60000

So the range = 60000 - 90000

So Answer - C
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 05:20
dimri10 wrote:
in a certain city 80% of the houses have cables and 60% have VCR. what is the range of houses that have both cables and a VCR, if there are 150,000 houses:(IN THOUSENDS)

1. 30-60
2. 30-90
3. 60-90
4. 60-150
5. 90-150

I used a table solving for NO CABLES/NO VCR=0 and then VCR/NO CABLES=0 to recieve the anser which seems correct.

is som1 can suggest a quicker method?

kind regards


The range is 40% - 60% hence
60k - 90K
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 05:33
subhashghosh wrote:
The highest range can be the # of people who have both Cables and VCR, which means 60% of people have cables, and VCR too.

So 60% of people = 60/100 * 150000 = 90000

Then again, the least overlap can be like :

80% + 60% - 100% = 40%

40% of 150000 = 40/100 * 150000 = 60000

So the range = 60000 - 90000

So Answer - C



thank's great reply.
but in the same subject:

is there a way to deal with sets without Venn diagrams?
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 05:37
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Well, to my mind, Venn diagrams make visualization easier. I think Venn diagrams are great, you can try the how to draw Venn diagrams by Whiplash, I think it's really good stuff.

Sometimes, double matrix is also good, especially for 2 sets, but it's really based on individual comfort level.
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 06:14
well i tried whiplash's way. it's too long in comparison to:

150=58+88+53-both-2*all.
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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New post 13 Jun 2011, 23:04
40 - 60% giving 60-90.
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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Re: in a certain city 80% of the houses have cables and 60% have VCR. what   [#permalink] 06 May 2016, 10:34
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