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In a certain city, the ratio of number of people who

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In a certain city, the ratio of number of people who [#permalink] New post 25 Oct 2008, 08:19
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In a certain city, the ratio of number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y.

(1) 27% of the population purchases neither newspaper X nor newspaper Y
(2) 70% of the people who purchase newspaper Y also purchase newspaper X
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Re: DS : Kaplan : Percentages [#permalink] New post 25 Oct 2008, 12:14
amitdgr wrote:
In a certain city, the ratio of number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y.

(1) 27% of the population purchases neither newspaper X nor newspaper Y
(2) 70% of the people who purchase newspaper Y also purchase newspaper X


A
x:y :: 7:1

1. 73% will buy either x or yor both - This is where I feel I could be making the mistake :roll:
8a = 73%
a = 9.1%
Y = 9.1% - Sufficeint

2. In Suff
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Re: DS : Kaplan : Percentages [#permalink] New post 25 Oct 2008, 12:35
amitdgr wrote:
In a certain city, the ratio of number of people who purchase newspaper X to the number of people who purchase newspaper Y is 7:1. What percent of the population purchases newspaper Y.

(1) 27% of the population purchases neither newspaper X nor newspaper Y
(2) 70% of the people who purchase newspaper Y also purchase newspaper X


y = x , x = 7x

population say = 1000

from 1

730/8.........suff

from 2

insuff

A
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Re: DS : Kaplan : Percentages [#permalink] New post 25 Oct 2008, 23:58
Given OA is C :(
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Re: DS : Kaplan : Percentages [#permalink] New post 26 Oct 2008, 22:15
amitdgr wrote:
Given OA is C :(


Amit, could you check if something is missing in the question posted? With the current wordings, A seems to be sufficient.
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Re: DS : Kaplan : Percentages [#permalink] New post 26 Oct 2008, 22:39
attaching the screen-shot.

I had also picked A.
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kaptest.jpg [ 106.86 KiB | Viewed 875 times ]


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Re: DS : Kaplan : Percentages [#permalink] New post 27 Oct 2008, 00:00
Thanks Amit for the posting. Now I understand what I was overlooking. Basically, the raio of 7:1 is of numbers and from stmt1: we only know of the percentage of union. Hence, this will not be sufficient to get the desired ratio.
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Re: DS : Kaplan : Percentages [#permalink] New post 27 Oct 2008, 00:08
scthakur wrote:
Thanks Amit for the posting. Now I understand what I was overlooking. Basically, the raio of 7:1 is of numbers and from stmt1: we only know of the percentage of union. Hence, this will not be sufficient to get the desired ratio.


how do we calculate using the 2 statements ?
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Re: DS : Kaplan : Percentages [#permalink] New post 27 Oct 2008, 00:20
amitdgr wrote:
scthakur wrote:
Thanks Amit for the posting. Now I understand what I was overlooking. Basically, the raio of 7:1 is of numbers and from stmt1: we only know of the percentage of union. Hence, this will not be sufficient to get the desired ratio.


how do we calculate using the 2 statements ?



Suppose, p is the total population then
from stmt1: 0.73p = XUY = X + Y + X intersection Y = 8Y + X intersection Y....insufficient.

From stmt2: X intersection Y = 0.7Y.

Combining two,
0.73p = 8.7Y and hence, Y/p can be determined.
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Re: DS : Kaplan : Percentages [#permalink] New post 27 Oct 2008, 02:33
I found my mistake too :)
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Re: DS : Kaplan : Percentages [#permalink] New post 25 Dec 2008, 14:34
Question stem:
Let P=population
X/Y = 7
Y/P=?
_______________

XuY - union of X and Y
X_Y - intersection of X and Y

Stmt 1: X_Y/P=0.27
Stmt 2: Y/XuY=0.7

Neither statement alone is suff. So, either C or E.
P=X+Y-XuY+X_Y - we need to see if we can make this expression consisting of P and Y only.
From stem: X=7Y;
from stmt1: X_Y=0.27P
from stmt2: XuY=Y/0.7
Replacing for the above we have : P = 7Y + Y- Y/0.7 +0.27P;
We can bring the above to Y/P form. So answer should be C.
Let me know you spot any mistake.
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Re: DS : Kaplan : Percentages [#permalink] New post 25 Dec 2008, 19:42
I also choose C.

Statement 1 provides us the total percentage of population who buy newspaper, that is 73% total population. but it is insufficient to conclude that in this 73%, the people buy A:B = 7:1 because many people buy B also buy A.

we put the number who buy B = X, then according to the ratio A:B = 7:1 then number buy A = 7X. So the number who buy newspaper could be X+7X subtract the number of people who buy both A and B = total 73% population

Use the statement 2, we know that 70% people buy B also buy A and we have this number equal to 0.7X. This number should be subtracted from the total.

Then we get X+7X - 0.7X = 7.3X = 73% population => x =10%.

So it is C
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Re: DS : Kaplan : Percentages [#permalink] New post 27 Dec 2008, 09:08
scthakur wrote:
amitdgr wrote:
scthakur wrote:
Thanks Amit for the posting. Now I understand what I was overlooking. Basically, the raio of 7:1 is of numbers and from stmt1: we only know of the percentage of union. Hence, this will not be sufficient to get the desired ratio.


how do we calculate using the 2 statements ?



Suppose, p is the total population then
from stmt1: 0.73p = XUY = X + Y + X intersection Y = 8Y + X intersection Y....insufficient.

From stmt2: X intersection Y = 0.7Y.

Combining two,
0.73p = 8.7Y and hence, Y/p can be determined.



Why you put X + Y = 8Y, 8Y also include those population which buy both X & Y. SO for me you can't replace it directly.

I still think there is issue in question it self. If question is such that :
Find the population which buy
ONLY paper Y
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Re: DS : Kaplan : Percentages [#permalink] New post 27 Dec 2008, 14:48
I concur with amitgupta that the questions should be " Y only ".
Re: DS : Kaplan : Percentages   [#permalink] 27 Dec 2008, 14:48
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